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frez [133]
4 years ago
9

How many valence electrons does the element with the following electron configuration have? 1s22s22p63s23p64s23d104p4

Chemistry
1 answer:
sesenic [268]4 years ago
5 0

Explanation:

please refer to the attached file (English)

s'il vous plaît se référer au fichier ci-joint cher compagnon (French)

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what is the specific latent heat of fusion for a substance that takes 550 kj to melt 14 kg at 262 k? brainly answers
Ket [755]

q = mL

L = q/m = 550 kJ/14 kg = 39 kJ/kg

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3 years ago
Match each label below with the appropriate term. Note there may be more than one correct answer.
irina1246 [14]

Answer:

sigma bond

represents two electrons

Explanation:

The bond between hydrogen and oxygen is sigma bond because the bond between hydrogen and oxygen is covalent means sharing of electron takes place between two atoms and we know that sigma bond is also occurs in a covalent bond in which overlapping of atomic orbitals or hybrid orbitals along the bond axis occurs. Both also represent two electrons because both atoms share one electron each so we can say that the two atoms represents two electrons.

5 0
3 years ago
What concentration of OH is required to created a pOH of 1.3.
Crank

Answer:

0.0501

Explanation:

OH=10^-poH

OH=10^-1.3

=0.0501

6 0
3 years ago
Force and distance are used to calculate work, work is measured in
Natali [406]
Work is measured in joules. hope this helps!
7 0
3 years ago
Read 2 more answers
A 1.25g sample of dry ice is added to a 765mL flask containing nitrogen gas at a temperature of 25.0°C and a pressure of 725 mmH
erica [24]

Answer : The total pressure in the flask is 1.86 atm.

Explanation :

First we have to calculate the pressure of CO_2 gas.

Using ideal gas equation :

PV=nRT\\\\P_{CO_2}=\frac{w}{M}\frac{RT}{V}

where,

P = Pressure of CO_2 gas = ?

V = Volume of CO_2 gas = 765 mL = 0.765 L     (1 L = 1000 mL)

n = number of moles

w = mass of CO_2 gas = 1.25 g

M = molar mass of CO_2 gas = 44 g/mol

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of CO_2 gas = 25.0^oC=273+25.0=298K

Putting values in above equation, we get:

P_{CO_2}=\frac{w}{M}\frac{RT}{V}

P_{CO_2}=\frac{1.25g}{44g/mol}\frac{(0.0821L.atm/mol.K)\times 298K}{0.765L}=0.909atm

Now we have to calculate the total pressure in the flask.

P_T=P_{N_2}+P_{CO_2}

Given :

P_{CO_2}=0.909atm

P_{N_2}=725mmHg=\frac{725}{760}=0.954atm

conversion used : (1 atm = 760 mmHg)

Now put all the given values in the above expression, we get:

P_T=0.954atm+0.909atm=1.86atm

Therefore, the total pressure in the flask is 1.86 atm.

5 0
3 years ago
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