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tatyana61 [14]
3 years ago
5

What is the percent composition of each of the elements in Al(OH) 3 ?

Chemistry
2 answers:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

%Al = 34.6%

%0 = 61.5%

%H = 3.9%

Explanation:

Al(OH)3

Atomic mass of Aluminum Al = 27

Atomic mass of Oxygen O=16

Atomic mass of Hydrogen H=1

Molar mass of Al(OH)3 = 27 + (16*3) + (1*3)

Al(OH)3 = 27 + 48 + 3

Al(OH)3 = 78

Percentage composition;

Aluminum Al= (27/78) × 100

Aluminum Al=0.346 × 100 =34.6%

Oxygen O=(16*3/78) × 100

Oxygen O= 0.615 × 100 =61.5%

Hydrogen H= (1*3/78) × 100

Hydrogen H=0.039 × 100=3.9%

stellarik [79]3 years ago
3 0

Answer:

<em>Answer Below</em>

Explanation:

Percent composition by element

<u>Element </u>       <u>Symbol</u>  <u>Mass Percent</u>

Aluminium <u>Al</u>          34.590%

Hydrogen <u>H</u>          3.877%

Oxygen         <u>O</u>          61.533%

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Answer:

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Explanation:

The steps of the Ostwald process:

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2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g)

3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g)

Combinning the equations:

4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)

+

(2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g))*2

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4 NH_3 (g)+ 4 NO (g)+ 7 O_2 (g) + 4 NO_2 (g) +4/3 H_2O (l) \longrightarrow 4 NO (g) + 6 H_2O (g) +  4 NO_2(g) + 8/3 HNO_3 (g) + 4/3 NO (g)

Simplifying:

4 NH_3 (g)+ 7 O_2 (g) + \longrightarrow  14/3 H_2O (l) + 8/3 HNO_3 (g) + 4/3 NO (g)

12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow  14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)

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4 0
3 years ago
What is the pressure of nitrogen in atmospheres of a sample that is at 745 mmHg?
Semenov [28]
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3 years ago
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Answer:

The answer to the question is

The rate constant for the reaction is 1.056×10⁻³ M/s

Explanation:

To solve the question, e note that

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Therefore the rate constant k which is the gradient is given by

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3 0
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The following are the steps  to complete and balnce the equation for the given reaction

<u>Explanation:</u>

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Step 2) Balance the element other than O and H

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Step 3) Balance the O by adding 1 H2O for 1 O

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Step 4) Balance the H by adding H+

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Step 5) Balance the charge by adding electron

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Step 6) Balance the electron in both half reaction

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     2 Ag+ + 2e------> 2 Ag(s)

3 0
3 years ago
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