Answer:
K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J
Explanation:
First we calculate the energy of photon:
E = hc/λ
where,
E = Energy of Photon = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength = 120 nm = 1.2 x 10⁻⁷ m
Therefore,
E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(1.2 x 10⁻⁷ m)
E = (16.565 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)
E = 10.35 eV
Now, from Einstein's Photoelectric equation we know that:
Energy of Photon = Work Function + K.E of Electron
10.35 eV = 4.82 eV + K.E
K.E = 10.35 eV - 4.82 eV
<u>K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J</u>
Answer:
gathered by using measurement tools and math
Explanation:
Quantitative data is often gathered by using measurement tools and math.
A quantitative data set is assigned values and numbers in order to solve a problem or for the purpose of a study.
- Each data set has a unique numerical value and can be counted.
- Qualitative data set does not use numerals and numbers.
- It engages the senses to make some scientific deductions.
- Examples are measurement of volume, distance, length, time, number of moles e.t.c
- Qualitative data sets include taste, smell, color e.t.c
Answer:
1.67×10^-11 N
Explanation:
m1 = 0.13kg
m2 = 0.34kg
d = 0.42m
G = 6.674 × 10 ^−11
F = Gm1m2/r²
F= (6.674 × 10^ −11×0.13×0.34)/(0.42)²
F = 1.67×10^-11 N
Answer:
False
Explanation:
Though fiber active cable is based on the concept of internal reflection but it is achieved by refractive index which transmit data through fast traveling pulses of light. It has a layer of glass and insulating casing called “cladding,”and this is is wrapped around the central fiber thereby causing light to continuously bounce back from the walls of the Cable.
