Answer:
the distance traveled by Charlotte in feet is 338.44 ft
Explanation:
Given;
speed of Charlotte, u = 66.5 mi/h
time of motion, t = 3.47 s
The distance traveled by Charlotte in feet is calculated as;
Therefore, the distance traveled by Charlotte in feet is 338.44 ft
The acceleration that the same force will provide if both masses are tied together is; 6.0 m/s².
<h3>How to find the Acceleration?</h3>
We are given;
Force; F = 5 N
Acceleration of the first mass, a₁ = 8.0 m/s²
Acceleration of the second mass, a₂ = 24 m/s²
Formula for force is;
F = ma
Let us find both masses; m₁ and m₂.
m₁ = F/a₁
m₂ = F/a₂
Thus;
m₁ = 5/8 kg
m₂ = 5/24 kg
Total mass is; m = m₁ + m₂
m = 5/8 + 5/24
m = 15 + 5/24
m = 20/24 kg
Thus, acceleration if they are both tied together is;
a = F/m
a = 5/(20/24)
a = 6.0 m/s².
Read more about Acceleration at; brainly.com/question/605631
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Answer:
Id say C
Explanation:
The hypotenuse for c is up and to the right so the unit vectors show that
<span>Easy, take the top off your Thermos bottle filled with hot coffee. Assuming perfect insulation, that hot coffee is isolated from the environment; but when the top is opened the heat can now escape to that environment.
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