What is the chemical formula of iron (III) sulfide? A. FeS B. Fe2S3 C. Fe2(SO3)3

Se tiene un litronde solucion de agua con alcohol con una consentracion del 4.5% v/v ¿Cuanto alcohol se tiene en la solución

Vinvika [58]

Answer:

45 mL

Explanation:

Tenemos los siguientes datos:

V = 1 L

C = 4,5% v/v

El porcentaje en volumen (%v/v) expresa el volumen de soluto (alcohol en este caso) que hay cada 100 mL de solución. Si la solución tiene una concentración del 4,5% v/v eso quiere decir que hay 4,5 ml de alcohol cada 100 ml de solución, de acuerdo a lo siguiente:

4,5% v/v alcohol = volumen alcohol/ volumen solución x 100 = 4,5 mL alcohol/100 mL solución= 4,5 mL alcohol/0,1 L alcohol

Por lo tanto, al multiplicar por el volumen total de la solución (1 L), obtenemos la cantidad total de alcohol:

4,5 mL alcohol/0,1 L alcohol x 1 L = 45 mL

3 0

2 years ago

Integrated rate law for second order unimolecular irreversible

kirill115 [55]

Answer:

The rate law for second order unimolecular irreversible reaction is

$\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }$

Explanation:

A second order unimolecular irreversible reaction is

2A → B

Thus the rate of the reaction is

$v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}$

rearranging the ecuation

$-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}$

Integrating between times 0 to t and between the concentrations of $[A]_{0}$ to [A].

$\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}$

Solving the integral

$\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }$

5 0

3 years ago

Yeast converts glucose to ethanol and carbon dioxide during a process known as anaerobic fermentation. The chemical reaction is

Korolek [52]

Answer:

102g

Explanation:

To find the mass of ethanol formed, we first need to ensure that we have a balanced chemical equation. A balanced chemical equation is where the number of atoms of each element is the same on both sides of the equation (reactants and products). This is useful as only when a chemical equation is balanced, we can understand the relationship of the amount (moles) of reactant and products, or to put it simply, their relationship with one another.

In this case, the given equation is already balanced.

$\tex{C_6H_{12}O_6} \longrightarrow 2 \ C_2H_6O + 2 \ CO_2$

From the equation, the amount of ethanol produced is twice the amount of yeast present, or the same amount of carbon dioxide produced. Do note that amount refers to the number of moles here.

Mole= Mass ÷Mr

Mass= Mole ×Mr

Method 1: using the mass of glucose

Mr of glucose

= 6(12) +12(1) +6(16)

= 180

Moles of glucose reacted

= 200 ÷180

= $\frac{10}{9}$ mol

Amount of ethanol formed: moles of glucose reacted= 2: 1

Amount of ethanol

= $2(\frac{10}{9} )$

= $\frac{20}{9}$ mol

Mass of ethanol

= $\frac{20}{9} \times[2(12)+6+16]$

= $\frac{20}{9}(46)$

= 102 g (3 s.f.)

Method 2: using mass of carbon dioxide produced

Mole of carbon dioxide produced

= 97.7 ÷[12 +2(16)]

= 97.7 ÷44

= $\frac{977}{440}$ mol

Moles of ethanol: moles of carbon dioxide= 1: 1

Moles of ethanol formed= $\frac{977}{440}$ mol

Mass of ethanol formed

= $\frac{977}{440} \times[2(12)+6+16]$

= 102 g (3 s.f.)

Thus, 102 g of ethanol are formed.

Additional:

For a similar question on mass and mole ratio, do check out the following!

brainly.com/question/1685725

8 0

1 year ago

If you are given the molarity of a solution, what additional information would you need to find the weight/weight percent (w/w%)

Ludmilka [50]

Answer:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

Explanation:

Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

$w/w\%=1\frac{molHCl}{L\ sln}*\frac{36.45gHCl}{1molHCl}*\frac{1L\ sln}{1000mL\ sln}*\frac{1mL\ sln}{1.125g\ sln} *100\%\\\\w/w\%=3.15\%$

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.

Regards.

4 0

2 years ago

How many moles are in 48.0g of H2O2?

Tju [1.3M]

Answer:

1.41 moles H2O2(with sig figs)

Explanation:

okay so what is the molar mass of H2O2= (1.008 g/mol)2+(16.00g/mol)2= (2.016+ 32.00) g/ mol

= 34. 02 g/mol

48.0g H2O2* 1 mol H2O2/ 34.02 g H2O2= 1.41 mol H2O2

3 0

2 years ago