Answer:
10.5 g
Explanation:
Step 1: Given data
- Molar concentration of the solution (C): 0.243 M
- Volume of solution (V): 0.580 L
Step 2: Calculate the moles of solute (n)
Molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
n = M × V
n = 0.243 mol/L × 0.580 L = 0.141 mol
Step 3: Calculate the mass corresponding to 0.141 moles of KCl
The molar mass of KCl is 74.55 g/mol.
0.141 mol × 74.55 g/mol = 10.5 g
The answer would be B) Lower, because pure water freezes at 32 degrees Fahrenheit whereas salt water freezes at 28.4 degrees Fahrenheit. Hopefully this helps!
Answer:calcium
Explanation: calcium is an alkaline earth metal,group 2 period 4
Answer:
These tests determine the solubility of the compounds formed upon adding the test solution
Explanation:
Addition of Ba(NO₃)₂ will cause a precipitate ((Ba)₂SO₄) to form in the solution of (NH₄)₂SO₄. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is ammonium sulfate can be determined.
Addition of NaCl solution will cause a precipitate (AgCl) to form in the solution of AgNO₃. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is silver nitrate can be determined.
If no precipitates form, then the unknown solution must be KCl.