All categories

3 years ago

Can someone answer these and show work please??

Physics

1 answer:

Nataliya [291]3 years ago

8 0

3. n=1.31. So using Snell's Law of Refraction, n1sinθ=n2sinθ. Your second theta should be 15 degrees instead. The angle is ALWAYS from the vertical. Since n of air is just 1, n2=(sin45)/(sin15)=1.31.

4. This is a bit interesting, the way YOU set this up. Because I am a physicist, the dashed line for refracting angles should be perpendicular to the object's surface. Whether that is how you are told by your instructor, or your own doing, I digress. Anyway, Snell's Law again, n1sinθ=n2sinθ. N of air is 1 at an angle of 90 degrees. So 1=sin90 for both shapes. Your angle for the triangular prism is 55 degrees, so n=1/sin(55). For the funky looking shape, your angle should actually be 90-35. ANGLE IS TO THE DASHED LINE, NOT THE SURFACE. So this n is 1/sin(55) again.

You got this

You might be interested in

The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance

belka [17]

The gravitational force between the spheres is

$F_{\rm g}=\dfrac{G(188\,\mathrm{kg})(0.93\,\mathrm{kg})}{(0.27\,\mathrm m)^2}\approx1.6\times10^{-7}\,\mathrm N$

where <em>G</em> = 6.674 x 10⁻¹¹ N m²/kg².

The weight of the lighter sphere is

$F_{\rm w}=(0.93\,\mathrm{kg})g\approx9.1\,\mathrm N$

where <em>g</em> = 9.80 m/s².

The ratio between the two forces is then

$\dfrac{F_{\rm g}}{F_{\rm w}}\approx1.8\times10^{-8}$

7 0

3 years ago

In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80m/

polet [3.4K]

V o - initial velocity
v = velocity at the maximum height,
v² = v o² - 2 g h
v = 0
0 = v o² - 2 g h
v o² = 2 g h = 2 · 9.80 · 0.460
v o² = 9.052
v o = √9.052 = 3.004197 m/s ≈ 3 m/s

8 0

4 years ago

A syringe containing 12.0 mL of dry air at 25 C is placed in a sterilizer and heated to 100.0 C. The syringe is sealed, but th

monitta

Answer:

15.01 Liters

Explanation:

T₁ = Initial temperature = 25°C = 298.15 K

T₂ = Final temperature = 100°C = 373.15 K

V₁ = Initial volume = 12 mL

Here, pressure is constant so we apply Charles Law

$\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\Rightarrow {V_2}=\frac{V_1}{T_1}\times T_2\\\Rightarrow {V_2}=\frac{12}{298.15}\times 373.15\\\Rightarrow {V_2}=15.01 L$

∴ Final volume at 100°C is 15.01 Liters.

5 0

4 years ago

un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en l

Dmitriy789 [7]

Answer:

Acceleration = 5.77 m/s²

Distance cover in 13 seconds = 487.56 meter

Explanation:

Given:

Final velocity of mobile device = 75 m/s

initial velocity of mobile device = 0 m/s

Time taken = 13 seconds

Find:

Acceleration

Distance cover in 13 seconds

Computation:

v = u + at

75 = 0 + (a)(13)

13a = 75

a = 5.77

Acceleration = 5.77 m/s²

s = ut + (1/2)(a)(t²)

s = (0)(t) + (1/2)(5.77)(13²)

Distance cover in 13 seconds = 487.56 meter

8 0

3 years ago

A car of mass 1,000 kilograms is moving initially at the speed of 22 meters/second. When the brakes are applied, it takes the ca

Mariulka [41]

i believe it is C....tell me if im right please<3

4 0

3 years ago

Read 3 more answers