All categories

2 years ago

Can someone answer these and show work please??

Physics

1 answer:

Nataliya [291]2 years ago

8 0

3. n=1.31. So using Snell's Law of Refraction, n1sinθ=n2sinθ. Your second theta should be 15 degrees instead. The angle is ALWAYS from the vertical. Since n of air is just 1, n2=(sin45)/(sin15)=1.31.

4. This is a bit interesting, the way YOU set this up. Because I am a physicist, the dashed line for refracting angles should be perpendicular to the object's surface. Whether that is how you are told by your instructor, or your own doing, I digress. Anyway, Snell's Law again, n1sinθ=n2sinθ. N of air is 1 at an angle of 90 degrees. So 1=sin90 for both shapes. Your angle for the triangular prism is 55 degrees, so n=1/sin(55). For the funky looking shape, your angle should actually be 90-35. ANGLE IS TO THE DASHED LINE, NOT THE SURFACE. So this n is 1/sin(55) again.

You got this

You might be interested in

Which seismic waves are generally the last to arrive after an earthquake?

34kurt

You're answer is B. P waves are more dynamic and have a great autonomy to be able generate a earthquake.

5 0

3 years ago

An alpha particle (Î±), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elec

vaieri [72.5K]

Answer:

Speed = 575 m/s

Mechanical energy is conserved in electrostatic, magnetic and gravitational forces.

Explanation:

Given :

Potential difference, U = $-3.45 \times 10^{-3} \ V$

Mass of the alpha particle, $m_{\alpha} = 6.68 \times 10^{-27} \ kg$

Charge of the alpha particle is, $q_{\alpha} = 3.20 \times 10^{-19} \ C$

So the potential difference for the alpha particle when it is accelerated through the potential difference is

$U=\Delta Vq_{\alpha}$

And the kinetic energy gained by the alpha particle is

$K.E. =\frac{1}{2}m_{\alpha}v_{\alpha}^2$

From the law of conservation of energy, we get

$K.E. = U$

$\frac{1}{2}m_{\alpha}v_{\alpha}^2 = \Delta V q_{\alpha}$

$v_{\alpha} = \sqrt{\frac{2 \Delta V q_{\alpha}}{m_{\alpha}}}$

$v_{\alpha} = \sqrt{\frac{2(3.45 \times 10^{-3 })(3.2 \times 10^{-19})}{6.68 \times 10^{-27}}}$

$v_{\alpha} \approx 575 \ m/s$

The mechanical energy is conserved in the presence of the following conservative forces :

-- electrostatic forces

-- magnetic forces

-- gravitational forces

5 0

3 years ago

If two stars are the same size and one is twice the temperature of the other, how much more luminous is the hotter one? quizlit

Dmitriy789 [7]

The hotter star will be 16 times more luminous - luminosity depends on two things - the size of the star and the temperature of the star. The hotter a star is, the more energy it will give out. This will give rise to greater luminosity.

3 0

3 years ago

Choose the best real world exzample of convection:

spin [16.1K]

The correct answer is A

3 0

3 years ago

Read 2 more answers

A low resistance light bulb and a high resistance light bulb are connected in parallel with each other. Which bulb is brighter i

sweet [91]

<h2>Answer:</h2>

The bulb with low resistance will be brighter.

<h2>Explanation:</h2>

The brightness of a bulb is a function of both the voltage across the bulb and current flowing through the bulb. The higher the voltage, the higher the current. Hence the brighter the bulb.

Now, according to the question, the bulbs (the high resistance bulb and the low resistance bulb) are connected in parallel with each other. This means that the same voltage passes across them.

Also, we know that according to Ohm's law, the voltage (V) and current (I) through a conductor are related by the following equation;

V = I x R -------------------(i)

Where;

R is the resistance of the conductor.

We can re-write equation (i) as follows;

I = V / R -----------------------(ii)

According to equation (ii), at fixed voltage (V), the current (I) will increase as the resistance (R) decreases.

Now, since the two bulbs have the same voltage, the bulb with the low resistance will allow a larger flow of current than the bulb with high resistance. Therefore, as said earlier that brightness is dependent on voltage and current, the bulb with the low resistance (and having larger current at some voltage) will be brighter than the bulb with the high resistance (having smaller current at same voltage).

6 0

3 years ago