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Anarel [89]
3 years ago
12

Can someone answer these and show work please??

Physics
1 answer:
Nataliya [291]3 years ago
8 0
3. n=1.31. So using Snell's Law of Refraction, n1sinθ=n2sinθ. Your second theta should be 15 degrees instead. The angle is ALWAYS from the vertical. Since n of air is just 1, n2=(sin45)/(sin15)=1.31.

4. This is a bit interesting, the way YOU set this up. Because I am a physicist, the dashed line for refracting angles should be perpendicular to the object's surface. Whether that is how you are told by your instructor, or your own doing, I digress. Anyway, Snell's Law again, n1sinθ=n2sinθ. N of air is 1 at an angle of 90 degrees. So 1=sin90 for both shapes. Your angle for the triangular prism is 55 degrees, so n=1/sin(55). For the funky looking shape, your angle should actually be 90-35. ANGLE IS TO THE DASHED LINE, NOT THE SURFACE. So this n is 1/sin(55) again.

You got this
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A basketball player standing under the hoop launches the ball straight up with an initial velocity of v₀ = 3.25 m/s from 2.5 m a
matrenka [14]

Answer: 0.53m

Explanation:

According to the equation of motion v²= v₀²+2as

Since the body is launched upward, the final velocity at the maximum height will be "zero" since the body will momentarily be at rest at the maximum height i.e v = 0

Initial velocity given (v₀) = 3.25 m/s

The body is also under the influence of gravity but the acceleration due to gravity will be negative being an upward force (a = -g) and the distance (s) will serve as our maximum height (h)

The equation of motion will.now become

V = v₀² -2gh

Where v = 0 v₀ = 3.25m/s g = 10m/s h = ?

0 = 3.25² - 2(10)h

0 = 10.56 - 20h

-10.56 = -20h

h = 10.56/20

h = 0.53m

Therefore, the maximum height, h (in meters), above the launch point that the basketball will achieve is 0.53m

6 0
4 years ago
A coil has an inductance of 6.00 mH, and the current in it changes from 0.200 A to 1.50 A in a time interval of 0.300 s. Find th
Andre45 [30]

Answer:

0.026 V

Explanation:

Given that,

Inductance of the coil, L = 6 mH

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\epsilon=L\dfrac{dI}{dt}\\\\=6\times 10^{-3}\times \dfrac{1.5-0.2}{0.3}\\\\=0.026\ V

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5 0
3 years ago
The Electric Field 9.0m from a +25μC charge is 
salantis [7]

The electric field intensity generated by a single point charge is given by

E(r)=k\frac{q}{r^2}

where

k is the Coulomb's constant

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r is the distance from the charge


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E(9.0 m)=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{25 \cdot 10^{-6} C}{(9 m)^2}=2775 V/m

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What is the name given to group 18 on the periodic table?​
zhannawk [14.2K]

Answer:

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7 0
3 years ago
Consider a plastic rod that is being charged up by rubbing a wool cloth. It is then brought to an initially neutral metallic sph
anygoal [31]

Answer:

A) is repelled by the sphere

Explanation:

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3 years ago
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