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kolbaska11 [484]
3 years ago
10

Choose the best real world exzample of convection:

Physics
2 answers:
Arturiano [62]3 years ago
4 0
I think that it is B. I’m not completely sure. I hope that I helped
spin [16.1K]3 years ago
3 0
The correct answer is A
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What instrument uses a magnetic field to magnify imags up to 100000000?
Mariana [72]
Transmission electron microscope
5 0
3 years ago
A projectile is launched with a horizontal velocity of 20 m/s and an initial vertical velocity of 20 m/s. What is the projectile
cestrela7 [59]

Answer:

Vertical acceleration 9.8 m/s² downward

Horizontal acceleration 0.0 m/s²

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6 0
3 years ago
Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. What is the truck’s velocity?
gladu [14]

<u>Answer:</u>

The velocity of the truck is 34 m/s.

<u>Explanation:</u>

The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:

<em>p = mv</em>

Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.

So substituting the given values in the above formula to find the velocity of the truck.

Truck's velocity = \frac{40120}{1180} = 34 m/s.

3 0
3 years ago
A solid sphere with a radius of 50.0 cm has a total positive charge of 40.0 μC uniformly distributed in its volume. Calculate th
il63 [147K]

Answer:

E=2.88\times 10^5\ N/C                              

Explanation:

It is given that,

The radius of the solid sphere, R = 50 cm = 0.5 m

Charge on the sphere, q=40\ \mu C=40\times 10^{-6}\ C

We need to find the magnitude of the electric field r = 10.0 cm away from the center of the sphere. The electric field at point r away form the center of the sphere is given by :

E=\dfrac{kqr}{R^3}

E=\dfrac{9\times 10^9\times 40\times 10^{-6}\times 0.1}{0.5^3}

E=2.88\times 10^5\ N/C

So, the electric field 10.0 cm away from the center of the sphere is 2.88\times 10^5\ N/C. Hence, this is the required solution.              

7 0
3 years ago
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