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VladimirAG [237]
3 years ago
7

A 2,500 kg car traveling to the north is slowed down uniformly from 20.0 m/s by a 6,250 N braking force acting opposite the car'

s motion. a) What is the cars velocity after 2.50 s? b) How far does the car move during 2.50 s? c) How long does it take the car to come to a stop?
Physics
1 answer:
12345 [234]3 years ago
7 0
A. 13.75 m/s
b. 42.19 m
c. 8s
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Two 25.0N weights are suspended at opposite ends of a rope that passes over a frictionless pulley. What is the tension in the ro
goldenfox [79]

Answer:

tension in rope = 25.0 N

Explanation:

  • Two forces act on the suspended weight. The force coming down is the gravitational force and the upward force by the tension in the rope.
  • Since the suspended weight is not accelerating so that the net force will be zero. Therefore the tension in the rope should be 25 N.

       ∑F = F - W = 0

       so

       F = W

       so tension in rope = F  = T  = 25 N

8 0
3 years ago
In a certain electrolysis experiment involving Al3+ ions, 60.2 g of Al is recovered when a current of 0.352 A is used. How many
yawa3891 [41]

Answer:

30.5 x 10³ min.

Explanation:

Atomic weight of aluminium = 27

For the reaction

Al⁺³ + 3e  = Al

3 mole of electron is required by 1 mole of aluminium

3 x 96500 C of charge is required for 27 gram of aluminium

60.2 g aluminium will require

\frac{3\times96500}{27} \times60.2

645.47 x 10³ C

So charge required = 645.47 x 10³ C

Now Charge  = Current x time

Current ( given ) = 0.352A

Time = charge / current = 645.47 x 10³ / .352

=1833 x 10³ s

30.5 x 10³ minutes

6 0
4 years ago
In the great shopping cart race, two students push on shopping carts. A having twice the mass of B, with the same force applied
fiasKO [112]

B. cart B

Explanation:

The acceleration of each cart is given by Newton's second law:

F=ma

a=\frac{F}{m}

where F is the force applied, a is the acceleration and m is the cart's mass.

The force F applied is the same for the two carts, however the mass of cart A (mA) is twice than the mass of cart B (mB), so we can rewrite the two accelerations:

a_A = \frac{F}{m_A}=\frac{F}{2 m_B}

a_B = \frac{F}{m_B}

we see that the acceleration of cart B is twice the acceleration of cart A, therefore cart B will move faster and will win the race.


7 0
3 years ago
In an experiment, 50 g of each material were placed in a calorimeter with the same starting water volume and temperature. Which
eimsori [14]

Answer:it’s different materials have different abilities to transfer energy.

Explanation:

Just took it.

3 0
3 years ago
Read 2 more answers
A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 10.
Masja [62]

Answer:

0.368 cm

Explanation:

x = distance by which the mercury rise

d = depth of the water = 10 cm = 0.10 m

ρ = density of water = 1000 kgm⁻³

ρ' = density of mercury = 13600 kgm⁻³

P₀ = atmospheric pressure

Using equilibrium of pressure on both side

P₀ + ρ g d = P₀ + ρ' g (2x)

(1000) (0.10) = (13600) (2x)

x = 0.00368 m

x = 0.368 cm

8 0
3 years ago
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