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belka [17]
3 years ago
14

How many moles of methane occupy a volume of 2.00 l at 50.0°c and 0.500 atm answer?

Chemistry
1 answer:
Sauron [17]3 years ago
5 0
Data Given:
                  Pressure  =  P  =  0.5 atm
 
                  Volume  =  V  =  2.0 L

                  Temperature  =  T  =  50 °C + 273  =  323 K

                  Moles  =  n  =  ?

Solution:
              Let suppose the gas is acting Ideally, Then According to Ideal Gas Equation.

                              P V  =  n R T
Solving for n,
                              n  =  P V / R T

Putting Values,
                             n  =  (0.5 atm × 2.0 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 323 K)

                             n  =  0.0377 mol
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Au :)

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The empirical formula for a compound is C2H4NO. If its molar mass is 232.2 g/mol, what is the molecular formula of the compound?
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Empirical formula mass

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Molar mass=232.2g/mol

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Molecular formula

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2 years ago
Will xenon react to nitrogen and why?
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7 0
4 years ago
How many grams of Aspirin (acetylsalicylic acid) should we form in this reaction if we started with 2.08g of Salicyclic Acid?
Kamila [148]

Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₄H₆O₃: 1 mole
  • C₇H₆O₃: 1 mole
  • C₉H₈O₄: 1 mole
  • C₂H₄O₂: 1 mole

The molar mass of the compounds is:

  • C₄H₆O₃: 102 g/mole
  • C₇H₆O₃: 138 g/mole
  • C₉H₈O₄: 180 g/mole
  • C₂H₄O₂: 60 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • C₄H₆O₃: 1 mole ×102 g/mole= 102 grams
  • C₇H₆O₃: 1 mole ×138 g/mole= 138 grams
  • C₉H₈O₄: 1 mole ×180 g/mole= 180 grams
  • C₂H₄O₂: 1  mole ×60 g/mole= 60 grams

<h3>Mass of aspirin formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?

mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}

<u><em>mass of aspirin= 2.713 grams</em></u>

Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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