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slava [35]
3 years ago
13

The rubidium isotope 87Rb is a β emitter that has a half-life of 4.9 ✕ 1010 y that decays into 87Sr. It is used to determine the

age of rocks and fossils. Rocks containing the fossils of early animal have a ratio of 87Sr to 87Rb of 0.0040. Assuming that there was no 87Sr present when the rocks were formed, calculate the age of the fossils.
Physics
1 answer:
fredd [130]3 years ago
4 0

Answer:

t = 39.04 1010 year

Explanation:

This is a nuclear disintegration exercise that is governed by the equation.

     N = N0 e (-lam t)

The average life time is related to nuclear activity

      T ½ = ln 2 / lam

Let's use these two equations for exercise, let's start by finding nuclear activity

     Lam = ln 2 / T ½

     Lam = ln 2 / 4.9 10 10

    Lam = 0.14146 10-10 y-1

They tell us that the relationship atoms

      No / N = 0.0040

Let's look

       No / N = 1/0040

       N/No = 250                                                                                                                                                                                

Let's calculate the time

       (-lam t) = ln (N / No)

,        t = - 1 / lam ln (n / No)

        t = - 1 / 0.14146 10-10 ln (250)

        t = 39.04 1010 year

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7 0
3 years ago
A 2 kg blob of putty moving at 3 m/s slams into a 3 kg blob of putty at rest. Which blob has the most momentum prior to the coll
Ray Of Light [21]

initial momentum of 2 kg blob is given as

P_1 = m_1v_1

here we have

m_1 = 2kg

v_1 = 3m/s

P_1 = 3(2) = 6 kg m/s

initial momentum of 3 kg blob is given as

P_2 = m_2v_2

here we have

m_2 = 3kg

v_2 = 0m/s

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So initially 2 kg Blob has most momentum before they collide

5 0
3 years ago
From Kepler's third law, an asteroid with an orbital period of 8 years lies at an average distance from the Sun equal to:
bazaltina [42]

Answer:

The correct option is (B).

Explanation:

The Kepler's third law of motion gives the relationship between the orbital time period and the distance from the semi major axis such that,

T^2\propto a^3\\\\T^2=ka^3

It is mentioned that, an asteroid with an orbital period of 8 years. So,

(8)^2=ka^3\\\\64=ka^3\\\\a=(64)^{\dfrac{1}{3}}\\\\a=4\ AU

So, an asteroid with an orbital period of 8 years lies at an average distance from the Sun equal to 4 astronomical units.

7 0
3 years ago
Part A Magnetic field lines form closed loops Magnetic field lines form closed loops Around and through bar magnets. Through cur
alex41 [277]

Answer:

Magnetic field lines form closed loops around current carrying straight wires.

Explanation:

Magnetic field lines is known to form closed loop (which also serves as a bar magnet) around current carrying conductor in a magnetic field. This direction of the loop around the conductor either clockwise or anticlockwise will determine the direction of current in the conductor.

This directions can be determined using the Maxwell cockscrew or clenched fist rule.

According to clenched fist rule which states if the conductor is grasp with the right hand, the curled finger will point in the direction of the magnetic field and the thumb will point in the direction of the current.

Note that the magnetic field lines around the conductor also behaves like a bar magnet.

8 0
3 years ago
You hold glider A of mass 0.125 kg and glider B of mass 0.375 kg at rest on an air track with a compressed spring of negligible
umka2103 [35]

Answer:

0.2 m/s

Explanation:

m_A = Mass of glider A= 0.125 kg

m_B = Mass of glider B = 0.375 kg

u_A = Initial Velocity of glider A = 0 m/s

u_B = Initial Velocity of glider B = 0 m/s

v_A = Final Velocity of glider A = 0.6 m/s

v_B = Final Velocity of glider B

As linear momentum is conserved

m_{A}u_{A}+m_{B}u_{B}=m_{A}v_{A}+m_{B}v_{B}\\\Rightarrow v_B=\frac{m_{A}u_{A}+m_{B}u_{B}-m_{A}v_{A}}{m_{B}}\\\Rightarrow v_b=\frac{0+0-0.125\times 0.6}{0.375}\\\Rightarrow v_b=-0.2\ m/s

Magnitude of the glider B at this time is 0.2 m/s

8 0
3 years ago
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