The diameter of the football player's piston is 0.55 m
Given that the mass of the cheerleader(m) is 55 kg, mass of football player to be hold (M) is 130 kg, height of the players (h) is 1.30 m, radius of the piston corresponding to the diameter (r) is 0.09 m, Diameter of football player's piston (R), P1 is Pressure on the cheerleader's side, P2 is Pressure on the football player's side
Using Pascal's law,
This law states that if there is a change at a point of a body immersed in a fluid then that change will spread thoroughly to each and every point of the body.
The formula of hydraulic system is,
P1= P2
F1/A1 = F2/A2
mg/πr^2 = 4Mg/πR^2
m/r^2=4M/R^2
R^2=4M×r^2/m
By plugging the values, we get.,
R^2=(4×130×0.09^2)/55
R^2=4.21/55=0.076
R=√0.076 = 0.275 m
Hence, diameter of football player's piston is 0.55 m
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Answer:
1) electric current - ampere
2) force - joule
3 frequency - hertz
4) density - kilogram per cubic metre
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Explanation:
use the formula
speed = frequency x wavelength
330 = frequency x 0.372
330 / 0.372 = frequency
887 Hz = frequency
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For a star that has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 is mathematically given as
L=2.7*10^30w
<h3> What is its luminosity?</h3>
Generally, the equation for the luminosity is mathematically given as
L=4*\pi^2*b
Therefore
L=4*\pi^2*b
L=4* \pi *(2.83*10^{18})*2.7*10^{-8}
L=2.7*10^30
In conclusion, the luminosity
L=2.7*10^30w
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