Answer:
∑ τ =0, L₀ = 
Explanation:
In a circular turning movement, when the arms are extended and then contracted in two possibilities:
- They are lowered the force of gravity is what pulls them, the tension of the muscle becomes zero to allow this movement.
In this movement the force is vertical(gravity) and the movement of the center of mass of each arm is vertical, so that the work is the weight value of the arm by the distance traveled by the center of mass.
- Another possibility is that the arms have stuck to the body, in this case the person's muscles perform the force, this force is horizontal and the displacement is the horizontal of the center of mass of the arms from the extended position to the contracted
In these movements the torque of the external force is equal for each arm, but in the opposite direction, so they are canceled where a net torque of zero, this causes the angular momentum to be preserved, which changes is the moment of inertia of the system and therefore you must also change the angular velocity to keep your product constant
∑ τ =0
L₀ = 
I₀ w₀ = I w
Answer:
I will graduate on the year 2022
Answer:
138,516,546.9 horas.
Explanation:
Tenemos que usar la ecuación:
Velocidad = distancia/tiempo
Acá tenemos:
Velocidad = 0.3m/s
distancia = 149597870700 m
y queremos resolver la ecuación para el tiempo:
0.3m/s = 149597870700m/tiempo.
tiempo = 149597870700m/(0.3m/s) = 498,659,569,000 s
y sabemos que una hora tiene 3600 segundos, entonces si queremos transformar de segundos a horas tenemos:
498,659,569,000 s = (498,659,569,000/3600) h = 138,516,546.9 horas.
This type of a problem can be solved by considering energy transformations. Initially, the spring is compressed, thus having stored something called an elastic potential energy. This energy is proportional to the square of the spring displacement d from its normal (neutral position) and the spring constant k:

So, this spring is storing almost 12 Joules of potential energy. This energy is ready to be transformed into the kinetic energy when the masses are released. There are two 0.2kg masses that will be moving away from each other, their total kinetic energy after the release equaling the elastic energy prior to the release (no losses, since there is no friction to be reckoned with).
The kinetic energy of a mass m moving with a velocity v is given by:

And we know that the energies are conserved, so the two kinetic energies will equal the elastic potential one:

From this we can determine the speed of the mass:

The speed will be 7.74m/s in in one direction (+), and same magnitude in the opposite direction (-).