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Rom4ik [11]
3 years ago
12

The top priority in a lab setting is

Physics
1 answer:
SpyIntel [72]3 years ago
5 0
The answer is a.safety
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So your answer would be A!
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A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while
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(c)  As 'd' becomes doubled, energy decreases by the factor of 2

Explanation:

Energy stored in a parallel plate capacitor is given by:

U=\frac{1}{2}CV^2\\\\C=\frac{A\epsilon_{o}}{d}\\\\then\\\\U=\frac{1}{2}\frac{A\epsilon_{o}}{d}V^2--(1)\\\\

As capacitor remains connected to the battery so V remains constant. As can be seen from (1) that energy is inversely proportional to the separation between the plates so as 'd' becomes doubled, energy decreases by the factor of 2.

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