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snow_lady [41]
3 years ago
15

A 54.0 mL aliquot of a 1.60 M solution is diluted to a total volume of 218 mL. A 109 mL portion of that solution is diluted by a

dding 161 mL of water. What is the final concentration? Assume the volumes are additive g
Chemistry
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer: The final concentration is 0.16 M.

Explanation:

According to the dilution law:

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 1.60 M

V_1 = volume of stock  solution = 54.0 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 218 ml

Putting these values:

1.60\times 54.0=M_2\times 218

M_2=0.40M

Now 109 ml of this diluted solution is further diluted by adding 161 mL of water.

Again applying dilution law:

0.40\times 109=M_3\times (109+161)

0.40\times 109=M_3\times 270

M_3=0.16M

Thus the final concentration is 0.16 M

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lakkis [162]

Answer: 1.48 atmosphere

Explanation:

Pressure in kilopascal = 150

Pressure in atmosphere = ?

Recall that 1 atmosphere = 101.325 kilopascal

Hence, 1 atm = 101.325 kPa

Z atm = 150 kPa

To get the value of Z, cross multiply

150 kPa x 1 atm = 101.325 kPa x Z

150 kPa•atm = 101.325 kPa•Z

Divide both sides by 101.325 kPa

150 kPa•atm/101.325 kPa = 101.325 kPa•Z/101.325 kPa

1.48 atm = Z

Thus, 150 kPa is equivalent to 1.48 atmospheres

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3 years ago
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almond37 [142]
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This compound, an eight-carbon alkane, serves as the 100 octane standard for gasoline. It has five methyl groups, one quaternary
Reika [66]

Answer:

2,2,4-Trimethyl-pentane

Explanation:

Structural characteristics of the compound is as follows:

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Compound must have straight chain of 5 carbons.

Three methyl substituents are attached to 2 and 4 carbons.

Therefore, IUPAC name of the compound will be 2,2,4-Trimethyl-pentane.

5 0
3 years ago
What is the equilibrium constant, KC if the reaction is a gas phase reaction? (Ans.: Gas: KC = 0.328 dm3/mol)
valentina_108 [34]

Answer:

Equilibrium constant Kc = Qc = quotient of reactant(s) and product(s)

Kc = [C]x[D]y..../[A]m[B]n..... = 0.328dm3/mol, where [C]x[D]y is the product and [A]m[B]n is the reactant(Both in gaseous states)

Explanation:

When a mixture of reactants and products of a reaction reaches equilibrium at a given temperature, its reaction quotient always has the same value. This value is called the equilibrium constant (K) of the reaction at that temperature. As for the reaction quotient, when evaluated in terms of concentrations, it is noted as Kc.

That a reaction quotient always assumes the same value at equilibrium can be expressed as:

Qc (at equilibrium) = Kc =[C]x[D]y…/[A]m[B]n…

This equation is a mathematical statement of the law of mass action: When a reaction has attained equilibrium at a given temperature, the reaction quotient for the reaction always has the same value.

6 0
3 years ago
Can someone help me out please ? I am very stuck here
Alex17521 [72]
Hey there!

<span>Atomic Masses :
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H = <span>1.00794  a.m.u
N = </span><span>14.0067  a.m.u
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Therefore:

HNO3 = </span>1.00794 + 14.0067 + ( 15.9994 * 3 ) =>  <span>63.0128 g/mol</span>
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