<h3>
Answer:</h3>
2.125 g
<h3>
Explanation:</h3>
We have;
- Mass of NaBr sample is 11.97 g
- % composition by mass of Na in the sample is 22.34%
We are required to determine the mass of 9.51 g of a NaBr sample.
- Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.
In this case,
- A sample of 11.97 g of NaBr contains 22.34% of Na by mass
A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass
% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100
Mass of the element = (% composition of an element × mass of the compound) ÷ 100
Therefore;
Mass of sodium = (22.34% × 9.51 g) ÷ 100
= 2.125 g
Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g
3H + 3Br = HBr9 Organic chemistry mechanism
B will be the one I think tbh
Answer:
A, 18.4 and 34!
Explanation:
The Burette seems to have <em><u>~18.4</u></em> of the liquid? substance in it, and the Measuring Cylinder seems to have <em><u>~34</u></em> of the liquid? substance in it. <em><u>So, it is A!</u></em> :]
Hope this helps!!
