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Len [333]
3 years ago
5

Find the 14th term in the sequence 1, 1/3, 1/9, … Find the sum of the first 10 terms of the sequence above.

Mathematics
1 answer:
pychu [463]3 years ago
6 0

Answer:

This is a geometric progresion that begins with 1 and each term is 1/3 the preceeding term

   Let Pn represent the nth term in the sequence

 

   Then Pn = (1/3)^n-1

 

   From this P14 = (1/3)^13 = 1/1594323

 

5. The sum of the first n terms of a GP beginning a with ratio r is given by

   Sn = a* (r^n+1 - 1)/(r - 1)

 

   With n = 10, a = 1 and r = 1/3, S10 = ((1/3)^11 - 1)/(1/3 - 1) = 1.500

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7 0
3 years ago
And this one you need to evaluate it please show your work I need help
grandymaker [24]

Step-by-step explanation:

-5 + 2 - 8 - (-14) =

(-3) - 8 + 14 =

-11 + 14 =

3 =

not sure but here you go^^

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3 years ago
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ivan bought these two magazines. if the sales tax was 6.75% what was the total amount that he paid for the magazines
stich3 [128]
(6.75/ 100) X 4.95 = .334
For one magazine the sales tax is $0.334.
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5 0
3 years ago
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What is the answer? Please help
goblinko [34]

Answer:

A

Step-by-step explanation:

One and three hundred and four thousand

1+                             3/100+          4/1000

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