Question

If x =(20-4t^2) find average velocity between t=0and t=2sec​

Answer 1

Answer:

The average velocity is 8 unit per sec

Explanation:

Given as :

The Distance x = 20 - 4t²  unit

Change in time Δt = ( 2 - 0 ) s = 2 s

Let the velocity = V unit/s

∴   V = $\frac{\partial (20 - 4t^{2})}{\partial x}$

Or, V =  - 8t          unit/s

Now velocity at t = 0

V1 = - 8 × 0 =  0  unit/s

And   velocity  at t = 2 sec

V2 =  - 8 × 2 = - 16

So, Average velocity = $\frac{v2 - v1}{2}$ = $\frac{- 16 - 0}{2}$ = -8

Or, $\begin{vmatrix}V\end{vmatrix}$ = 8   unit/sec

Hence The average velocity is 8 unit per sec       Answer