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3 years ago

If x =(20-4t^2) find average velocity between t=0and t=2sec

Physics

1 answer:

lapo4ka [179]3 years ago

6 0

Answer:

The average velocity is 8 unit per sec

Explanation:

Given as :

The Distance x = 20 - 4t² unit

Change in time Δt = ( 2 - 0 ) s = 2 s

Let the velocity = V unit/s

∴ V = $\frac{\partial (20 - 4t^{2})}{\partial x}$

Or, V = - 8t unit/s

Now velocity at t = 0

V1 = - 8 × 0 = 0 unit/s

And velocity at t = 2 sec

V2 = - 8 × 2 = - 16

So, Average velocity = $\frac{v2 - v1}{2}$ = $\frac{- 16 - 0}{2}$ = -8

Or, $\begin{vmatrix}V\end{vmatrix}$ = 8 unit/sec

Hence The average velocity is 8 unit per sec Answer

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3 years ago

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4 years ago

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Answer:

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4 years ago

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lys-0071 [83]

Answer:

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3 years ago

If x =(20-4t^2) find average velocity between t=0and t=2sec​

If x =(20-4t^2) find average velocity between t=0and t=2sec