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maw [93]
3 years ago
14

Suppose you needed to measure exactly 15.0 mL of water for an

Chemistry
2 answers:
Alex787 [66]3 years ago
7 0

Answer:

A test tube would be used.

Explanation:

The test tube is a laboratory instrument which is a cylinder made of graduated glass used to measure small volumes of liquids (from 5 mL to 2 L). For the measurement of the volume of the liquid, the most appropriate type of specimen must be selected, in this case a 15 mL one. The specimen is closed at the bottom and has a base for support.

s344n2d4d5 [400]3 years ago
6 0

Answer:

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Explanation:

Hello,

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Best regards.

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Jim, Jill, Robert, and Kim each run paper chromatography on an unknown aqueous mixture. Jim gets a red band and a blue band, Jil
Romashka-Z-Leto [24]

Answer:

Robert

Explanation:

There is not more than one colour

4 0
3 years ago
If a container contains 3.5 moles and has a volume of 1.5 L, then what volume is it when it contains 8 moles? *
Lilit [14]
Volume would be 3.4 L
8 0
3 years ago
When a 12.8 g sample of KCL dissolves in 75.0 g of water in a calorimeter the temp. drops from 31 Celsius to 21.6 Celsius. Calcu
Delicious77 [7]

Answer:

Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

7 0
3 years ago
Express the following in scientific notation:<br><br> 1. 158000 km<br> 2. 0.000009782 L
slamgirl [31]

Answer:

1.58x10^5km

9.782x10^-6

Explanation:

Please Brainlist

6 0
2 years ago
I'll give brainliest.
Rasek [7]

Answer:

Below

Explanation:

Rocks layers break apart along fault lines releasing large amounts of energy

Brainliest pls :DDD

6 0
3 years ago
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