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maw [93]
3 years ago
14

Suppose you needed to measure exactly 15.0 mL of water for an

Chemistry
2 answers:
Alex787 [66]3 years ago
7 0

Answer:

A test tube would be used.

Explanation:

The test tube is a laboratory instrument which is a cylinder made of graduated glass used to measure small volumes of liquids (from 5 mL to 2 L). For the measurement of the volume of the liquid, the most appropriate type of specimen must be selected, in this case a 15 mL one. The specimen is closed at the bottom and has a base for support.

s344n2d4d5 [400]3 years ago
6 0

Answer:

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Explanation:

Hello,

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Best regards.

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Which element would lose electrons during ionic bonding choose all that apply
yawa3891 [41]

Answer:

All of them!

Explanation:

Since Mg, Li, Ca, and Cs are all in groups 1 and 2 of the periodic table, they are alkali/alkaline earth metals and will all lose electrons during ionic bonding.

7 0
2 years ago
What are the names of the stable forms of oxygen?
zloy xaker [14]

Answer:

18 O, 17 O, and 16 O

Explanation:

three naturally stable isotopes

5 0
2 years ago
Which of the following chemical reactions will produce a precipitate? *
Zolol [24]

Answer:

A

Explanation:

8 0
2 years ago
The decomposition of HBr(g) into elemental species is found to have a rate constant of 4.2 ×10−3atm s−1. If 2.00 atm of HBr are
Dennis_Churaev [7]

Answer:

7,94 minutes

Explanation:

If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>

For the zero-order reactions, concentration-time equation can be written as follows:

                                          [A] = - Kt + [Ao]

where:

  • [A]: concentration of the reactant A at the <em>t </em>time,
  • [A]o: initial concentration of the reactant A,
  • K: rate constant,
  • t: elapsed time of the reaction

<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>

Data:

K = 4.2 ×10−3atm/s,  

[A]o=[HBr]o= 2 atm,  

[A]=[HBr]=0 atm (all HBr(g) is gone)

<em>We clear the incognita :</em>

[A] = - Kt + [Ao]............. Kt =  [Ao] - [A]

                                        t  = ([Ao] - [A])/K

<em>We replace the numerical values:</em>

t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes

So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).

6 0
2 years ago
How does 2 Na (s) + Cl2 (g) = NaCl (s) represent the coefficient in the chemical equation
Elenna [48]

Answer:

The 2 would be placed in front of the reactant Na and in front of the product NaCl

2Na + Cl2 = 2NaCl

Explanation:

This is because the ratio of elements needs to be balanced on both sides.

On the reactants side, there are 2 Na molecules and 2 Cl molecules

On the products side, there are 2 Na molecules and 2 Cl molecules

So, now the equation is balanced

3 0
2 years ago
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