After some wood has completely burned in a fire some of the matter that made up the wood has been destroyed
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The given question is incomplete. The complete question is as follows.
Citrate synthase catalyzes the reaction
Oxaloacetate + acetyl-CoA citrate + HS-CoA
The standard free energy change for the reaction is -31.5 kJ*mol^-1
( a) Calculate the equilibrium constant for this reaction a 37degrees C
Explanation:
(a). It is known that
, relation between change in free energy () of a reaction and equilibrium constant (K) is as follows.
where, T = temperature in Kelvin
The given data is as follows.
T = 310 K, (as 1 kJ = 1000 J)
Now, putting the given values into the above formula as follows.
ln K =
=
ln K = 12.22
K = antilog (12.22)
=
Therefore, we can conclude that value of equilibrium constant for the given reaction is .
1) The metal which reduces the other compound is the one higher in the reactivity. So in this case it is .
2) The substance which brings about reduction while itself getting oxidised (that is losing electrons) is called a reducing agent. Here, $\mathrm{Zn}$ is the reducing agent and reduces Cobalt Oxide to Cobalt while itself getting oxidised to Zinc oxide.