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Sedaia [141]
4 years ago
12

When potassium metal is placed in water, a large amount of energy is released as potassium hydroxide and hydrogen gas are produc

ed in the reaction 2K(s) + 2H2O(l) → 2KOH(aq) + H2(g). Your lab partner says this is a redox reaction and a combustion reaction. Do you agree? Defend your answer by explaining whether or not it meets the requirements of each type of reaction.
Chemistry
1 answer:
blsea [12.9K]4 years ago
8 0

Answer: The given reaction redox reaction not a combustion reaction.

Explanation:

Redox Reaction is defined chemical reaction in which oxidation and reduction takes place simultaneously. In Oxidation addition of oxygen occurs and in reduction addition of hydrogen occurs.

2K+2H_2O\rightarrow 2KOH+H_2

Potassium is getting oxidized by addition of oxygen.

Water us reduced to hydrogen gas by removal of oxygen

Combustion reaction is defined as chemical reaction in which burning of a chemical compound or element takes place in presence of oxygen occurs.

In the given reaction, oxygen molecule is absent which means this reaction is not combustion reaction.

Hence ,the given reaction redox reaction not a combustion reaction.

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Catalysts are substances that speed up the rate of a chemical reaction. It is important to know that reacting species must first possess a minimum amount of energy equal to the activation energy for the reaction to proceed. The catalyst works in a way that lowers the activation energy required for the reaction to proceed. In this way, the reaction occurs at a faster rate than without a catalyst. Catalysts do not react with the chemical species in the reaction, thus, they are not consumed. However, over time, catalysts tend to degrade and their function is also reduced. When this happens, new catalysts replace the poisoned ones. Catalysts are widely used today since they bring an increase in the production rate of commercial chemicals.

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3 years ago
According to valence bond theory, which orbitals on N and H overlap in the NH3 molecule? 2p on N overlaps with 2s on H 2s on N o
Alecsey [184]

Answer:

sp^{3} on N overlaps with 1s on H.

Explanation:

Hybridization of central atom generally can be found by finding the hybridization number.Hybridization number is the sum of number of lone pairs and number of sigma bonds.

If hybridization number is 2 then the central atom is sp hybridized.

If it is 3 it is sp^{2} hybridized.

If it is 4 it is sp^{3} hybridized and so on.

Here in NH_{3} molecule there are 3 sigma bonds and one lone pair(see the figure attached).

Hence hybridization number is 4 and hence it is sp^{3} hybridized.

And in case of hydrogen atom the only electron of it resides in the 1s orbital.

Therefore sp^{3} on N overlaps with 1s on H.

8 0
4 years ago
I NEED HELP PLEASE, THANKS!
Crazy boy [7]

Answer:

Here's what I get.

Explanation:

1. Brønsted-Lowry theory

An acid is a substance that can donate a proton to another substance.

A  base is a substance that can accept a proton from another substance.

2. pH of ammonia

The chemical equation is

\rm NH$_{3}$ + \text{H}$_{2}$O \, \rightleftharpoons \,$ NH$_{4}^{+}$ + \text{OH}$^{-}$

For simplicity, let's re-write this as

\rm B + H$_{2}$O \, \rightleftharpoons\,$ BH$^{+}$ + OH$^{-}$

(a) Set up an ICE table.

                     B + H₂O ⇌ BH⁺ + OH⁻

I/mol·L⁻¹:     0.335             0        0

C/mol·L⁻¹:       -x                +x       +x

E/mol·L⁻¹:  0.335 + x          x         x

\rm K_{\text{b}} = \dfrac{\text{[BH}^{+}]\text{[OH}^{-}]}{\text{[B]}} = 1.8 \times 10^{-5}\\\\\dfrac{x^{2}}{0.335 - x} = 1.8 \times 10^{-5}

Check for negligibility:

\dfrac{0.335}{1.8 \times 10^{-5}} = 28 000 > 400\\\\x \ll 0.335

(b) Solve for [OH⁻]

\dfrac{x^{2}}{0.335} = 1.8 \times 10^{-5}\\\\x^{2} = 0.335 \times 1.8 \times 10^{-5}\\x^{2} = 6.03 \times 10^{-6}\\x = \sqrt{6.03 \times 10^{-6}}\\x = \text{[OH]}^{-} = \mathbf{2.46 \times 10^{-3}} \textbf{ mol/L}

(c) Calculate the pOH

\text{pOH} = -\log \text{[OH}^{-}] = -\log(2.46 \times 10^{-3}) = 2.61

(d) Calculate the pH

pH = 14.00 - pOH = 14.00 - 2.61 = 11.39

3 0
4 years ago
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