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3 years ago

Electrons surround the , of an atom in various energy levels called

Chemistry

1 answer:

nasty-shy [4]3 years ago

7 0

surrounds the nucleus of an atom in various energy levels called orbitals.

Explanation:

Electrons surrounds the nucleus of an atom in various energy levels called orbitals.

According to the Bohr's model of an atom, the extra nuclear space is made up of electrons in specific spherical orbits called shells or energy levels.

The region of a maximum probability of where an electron is located is sometimes referred to as an electron cloud or orbital.
Electrons move round the nucleus in certain permissible orbits.
An electron in an energy level posses a definite amount of energy associated with it at that level.
Electrons moves through the energy levels by gaining or losing energy.

Learn more:

Bohr brainly.com/question/4986277

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Describe the overall enthalpy of the chemical reactants compared to the enthalpy of the chemical products in the combustion of p

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Answer:

A thermochemical equation for the combustion of propane (C3H8)(C3H8) is written as follows:

C3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔH∘rxnC3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔHrxn∘ = -2202.0 kJ/mol

The value given for ΔH∘rxnΔHrxn∘ means that:

a. the reaction of one mole of propane absorbs 2202 kJ of energy from the surroundings.

b. the reaction is endothermic.

c. the enthalpy of formation of propane is 2202 kJ/mol.

d. the reaction of one mole of propane releases 2202 kJ of energy to the surroundings.

e. None of these.

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1 year ago

Choose all the answers that apply.

Rashid [163]

B:Creates energy through fusion reactions

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3 years ago

Read 2 more answers

Identify the most common reaction conditions for the dehydration of 2,3-dimethyl-2-pentanol.Select all that apply.A. The presenc

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Answer:

D. The presence of a base catalyst.

E. The presence of an acid catalyst. and

F. The presence of heat.

Explanation:

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3 years ago

Which is the correct Lewis dot structure of NH2?

Svetlanka [38]

Answer:

OE. E

Explanation:

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3 years ago

Carry out the following operations as if they were calculations of experimental results and express each answer in standard nota

Shalnov [3]

Answer:

1. $10.6\; \rm m$ (one decimal place.)

2. $0.79\; \rm g$ (two decimal places.)

3. $16.5\;\rm cm^2$ (three significant figures.)

Explanation:

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

$5.6792\;\rm m$ has four decimal places.
$0.6\; \rm m$ has only one decimal place.
$4.33\; \rm m$ has two decimal places.

Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: $\rm m$ .)

Therefore:

$\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m$ . (Rounded to one decimal place.)

Similarly:

$\rm 3.70\; \rm g$ has two decimal places.
$2.9133\; \rm g$ has four decimal places.

Therefore, the result should be rounded to two decimal places. Its unit should be $\rm g$ (same as the unit of the two inputs.)

$\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g$ . (Rounded to two decimal places.)

When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:

$4.51\; \rm cm$ has three significant figures.
$3.6666\; \rm cm$ has five significant figures.

Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be $\rm cm \cdot cm$ , which is occasionally written as $\rm cm^2$ .

$\rm 4.51 \; cm \times 3.6666 \; cm \approx 16.5\; \rm cm^2$ . (Rounded to three significant figures.)

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3 years ago