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Neporo4naja [7]

2 years ago

11

A motorcycle starts to move from rest. If the velocity of the motorcycle becomes 90 km/hr

1 answer:

bagirrra123 [75]2 years ago

6 0

Explanation:

90 kmhr—1 x 1000/3600 = 25ms—1

U = 0 ms—1

V = 25ms—1

t = 10 s

a = ?

a = V - U/t

a = 25 - 0/10

a = 25/10

a = 2.5 ms—1

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an aircraft has a liftoff speed of 53 m/s. what is the minimum constant acceleration an airplane must have to reach that takeoff

xxMikexx [17]

Answer:

$a=3.34\ m/s^2$

Explanation:

<u>Accelerated Motion </u>

It refers to the motion of objects in which velocity is not constant over time. If the change of the velocity occurs at the same rate, then we say it's uniformly accelerated. Being $v_o$ = initial speed, $v_f$ = final speed, a= constant acceleration, x= distance traveled

Then, the scalar relation between them is

$v_f^2=v_o^2+2ax$

The aircraft needs to reach a liftoff speed of 53 m/s from rest (assumed) having only 420 meters to do so. We can compute the acceleration by solving for a

$\displaystyle a=\frac{v_f^2-v_0^2}{2x}$

$\displaystyle a=\frac{53^2-0^2}{2(420)}$

$\boxed{a=3.34\ m/s^2}$

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3 years ago

The four wheels of a car are connected to the car's body by spring assemblies that let the wheels move up and down over bumps an

maksim [4K]

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The approximate spring constant is $k = 55533.33 \ N/m$

Explanation:

From the question we are told that

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Answer:

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F = $\frac{-Gm_{1}m_{2} }{r^{2} }$ .

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The answer is a for Plato users.

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