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olga2289 [7]
1 year ago
7

29. If a walnut is burned in a

Chemistry
1 answer:
harkovskaia [24]1 year ago
8 0

Energy were released from the walnut, q = 1,673.6 J

<h3>Equation :</h3>

To find the energy using formula,

q = mcΔt

where,

q is charge

m is mass

c is specific heat of water

Δt is change in temperature

So, given

t₁ = 50°C

t₂ = 60°C

m = 40g

c = 4.184 J/g

Now putting the values known,

We get,

q = mc(t₂ - t₁)

q = 40g x 4.184 J/g x  (60 - 50)

q = 167.36 J x 10

q = 1,673.6 J

<h3>What is heat energy?</h3>

Heat is the thermal energy that is transferred when two systems with different surface temperatures come into contact. Heat is denoted by the letters q or Q and is measured in Joules.

To know more about specific heat :

brainly.com/question/11297584

#SPJ9

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how to identify amphiprotic compounds, if i give you the chemical structure or name of the compound/molecule.
Sonja [21]

Amphiprotic compounds are able to both donate and accept a proton.

Amphiprotic compounds contain a hydrogen atom and lone pair of valence electron.

For example, HSO₃⁻ (hydrogen sulfate ion) is an amphiprotic compound.

Balanced chemical equation for reaction when HSO₃⁻ donate protons to water:

HSO₃⁻(aq) + H₂O(l) ⇄ SO₄²⁻(aq) + H₃O⁺(aq).

Ka = [SO₄²⁻] · [H₃O⁺] / [HSO₃⁻]

Balanced chemical equation for reaction when HSO₃⁻ accepts protons from water:

HSO₃⁻(aq) + H₂O(l) ⇄ H₂SO₄(aq) + OH⁻(aq).

Kb = [H₂SO₄] · [OH⁻] / [HSO₃⁻]

Water (H₂O), amino acids, hydrogen carbonate ions (HCO₃⁻) are examples of amphiprotic species.

Another example, water is an amphiprotic substance:

H₂O + HCl → H₃O⁺ + Cl⁻

H₂O + NH₃ → NH₄⁺ + OH⁻

More about amphiprotic compounds: brainly.com/question/3421406

#SPJ4

7 0
1 year ago
Part 1: Use complete sentences to explain why solar storms occur.
Virty [35]
A geomagnetic storm (commonly referred to as a solar storm) is a temporary disturbance of the Earth's magnetosphere caused by a solar wind shock wave and/or cloud of magnetic field that interacts with the Earth's magnetic field.


Solar flares, coronal mass ejections, high-speed solar wind, and solar energetic particles are all forms of solar activity.
4 0
3 years ago
WORTH 20 POINTS HELP PLEASE
Damm [24]

Answer:

The answers to your questions are below

Explanation:

Physical change is when matter changes its form but is still the same substance.

Chemical change is when matter changes its composition.

iron and oxygen from rust  It's a chemical change because iron and oxygen form a new compound different from the reactants.

iron is denser brightly when ignited . This is a chemical property because iron reacts with oxygen.

oil and water do not mix it's a physical change, oil and water are in touch but they do not react.

mercury melts at -39°C it's a physical property because mercury changes from solid to liquid but it still is mercury.

5 0
3 years ago
The position of the equilibrium for a system where K = 6.4 × 10 9 can be described as being favoring ________________
geniusboy [140]

Answer:

to the right (products side)

Explanation:

The equilibrium constant K describes the ratio between the concentration of products and reactants at equilibrium. For a general reaction:

a A + b B → c C + d D

The equilibrium constant expression is:

K = \frac{[C]^{c} [D]^{d}  }{[A]^{a} [B]^{b}  }

A low value of K indicates that the concentration of products (C and D) is low in relation with the concentration of reactants (A and B).

Conversely, a high value of K indicated that the concentration of products is high compared with the concentration of reactants.

Since K = 6.4 × 10⁹ is a high value, the concentration of products is higher than the concentration of reactants at equilibrium. Thus, the position of the equilibrium is favored to the right.

5 0
3 years ago
The energy gap between the valence band and the conduction band in the widely-used semiconductor gallium arsenide (GaAs) is Δ =
stira [4]

Answer:

n_e = 8.139 *10^6

Explanation:

Given that;

The energy gap between the valence band and the conduction band in the widely-used semiconductor gallium arsenide (GaAs) is Δ = 1.424 eV.

So; that implies that:

\delta \ E = 1.424 \ eV

Suppose that we consider a small piece of GaAs with 1020 available electrons, -- This is taking about the numbers of electrons used which is :

n_i = 10^{20} \ electrons

Temperature is given as:

T = 274.15 \ K

Number of electrons can be calculated by using the formula;

n_e = n_i*e^-^{\frac{\delta E }{2 K_B*T}}

n_e = 10^{20}*e^-^{\frac{1.424}{2*8.617*10^{-5}*274.15}}

n_e = 8.139 *10^6

8 0
3 years ago
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