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Greeley [361]
3 years ago
12

How do I do this question?

Physics
1 answer:
Mkey [24]3 years ago
5 0

a. 27

after that all you need to do is use the work formula as you will be able to acheive results

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The magnitude E of an electric field depends on the radial distance r according to E = A/r4, where A is a constant with unit vol
Lesechka [4]

Answer:

\Delta V = 0.053 A

Explanation:

Electric field in a given region is given by equation

E = \frac{A}{r^4}

as we know the relation between electric field and potential difference is given as

\Delta V = -\int E. dr

so here we have

\Delta V = - \int (\frac{A}{r^4}) .dr

\Delta V = \frac{A}{3r_1^3} - \frac{A}{3r_2^3}

here we know that

r_1 = 1.71 m  and r_2 = 2.89 m

so we will have

\Delta V = \frac{A}{3}(\frac{1}{1.71^3} - \frac{1}{2.89^3})

so we will have

\Delta V = 0.053 A

8 0
2 years ago
Which pair of equations can describe the path of a particle moving with an acceleration that is perpendicular to the velocity of
antoniya [11.8K]

Answer:

The question clearly describes the circular motion.

The circular motion equation is

a_{radial} = \frac{v^2}{r}

The path of the particle is circular.

Explanation:

In circular motion, the radial acceleration is always towards the center and constant in magnitude. Furthermore, the velocity of the circular motion is always tangential to the circle, that is it is always perpendicular to the radius, hence the acceleration.

6 0
2 years ago
The mountains most commonly found at divergent plate boundaries are
dybincka [34]
fault-block mountains. hope this helps
8 0
3 years ago
QUIZZ <br><br>12 + 14 + 66 - 87
svet-max [94.6K]

12 + 14 + 66 - 87

26+66-87

92-87

5

6 0
2 years ago
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A mass spectrometer applies a voltage of 2.00 kV to accelerate a singly charged positive ion. A magnetic field of B = 0.400 T th
N76 [4]

The mass of the ion is 5.96 X 10⁻²⁵ kg

<u>Explanation:</u>

The electrical energy given to the ion Vq will be changed into kinetic energy \frac{1}{2}mv^2

As the ion moves with velocity v in a magnetic field B then the magnetic Lorentz force Bqv will be balanced by centrifugal force \frac{mv^2}{r}.

So,

Vq = \frac{1}{2}mv^2

and

Bqv = \frac{mv^2}{r}

Right from these eliminating v, we can derive

m = \frac{B^2r^2q}{2V}

On substituting the value, we get:

m = \frac{(0.4)^2X (0.305)^2 X1.602X 10^-^1^9}{2X 2000}\\\\

m = 5.96 X 10⁻²⁵ kg.

3 0
3 years ago
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