Question

A sound wave in air has a pressure amplitude equal to 3.92 x 103 N/m2. Calculate the displacement amplitude of the wave at a frequency of 9.2 kHz. (Note: Use the 1.20 kg/m3; the speed of sound in air is v 343 m/s. Pressure variations AP are measured relative to following values, as needed. The equilibrium density of air is p atmospheric pressure, 1.013 x 105 Pa.)

Answer 1

Answer:

1.65 × 10⁻⁴ m

Explanation:

Displacement amplitude  = A = Δ P / 2πf ρv

= ( 3.92 × 10³) / 2π (9.2 × 10³) (1.20)(343)

= 1.65 × 10⁻⁴ m  

Displacement amplitude is the distance traveled by the wave particle from its equilibrium position.