Answer:
2.8 cm
Explanation:
= Separation between two first order diffraction minima = 1.4 cm
D = Distance of screen = 1.2 m
m = Order
Fringe width is given by
Fringe width is also given by
For second order
Distance between two second order minima is given by
The distance between the two second order minima is 2.8 cm
Answer:
2874.33 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Now H-h = 0.588 - 0.002 = 0.586 m
The final velocity will be the initial velocity
Acceleration of the frog is 2874.33 m/s²
Answer:
1÷60 h
time equals distance upon speed
<span>It's close to the sun without much atmosphere, so it's characterized by </span><span>very extreme temperatures.
Happy studying ^_^</span>