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andrey2020 [161]
3 years ago
10

How are nymphs different from adult insects?

Chemistry
2 answers:
umka2103 [35]3 years ago
4 0

Answer:

Explanation:

the nymph looks like a smaller version of the adult insect, & it also has no wings & molts.

Ede4ka [16]3 years ago
3 0

Answer:

tg n

Explanation:

/

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Generally, which of the three families of elements (metals, nonmetals, or inert gases) has the least tendency to form ionic bond
Sergio [31]

Answer:

Inert gases

Explanation:

Inert elements have a stable electron configuration meaning their shells/orbitals are full with their requisite number of electrons. Therefore, gaining or losing an electron would take high ionization energy. Therefore they are less likely to be involved in chemical reaction unless a high amount of energy is used. An example of an inert gas is Helium.

6 0
3 years ago
0.28gram of NH3 on decomposition gave 0.25gram of nitrogen and hydrogen. Find the volume of hydrogen evolved at Ntp. (2gram hydr
hodyreva [135]

The volume of H₂ evolved at NTP=0.336 L

<h3>Further explanation</h3>

Reaction

Decomposition of NH₃

2NH₃ ⇒ N₂ + 3H₂

conservation mass : mass reactants=mass product

0.28 NH₃= 0.25 N₂ + 0.03 H₂

2 g H₂ = 22.4 L

so for 0.03 g :

\tt \dfrac{0.03}{2}\times 22.4=0.336

7 0
2 years ago
Given the following equation: 2 K + Cl2 ---&gt; 2 KCl
Ksivusya [100]

Answer:

2 moles of KCl will be produced

Explanation:

Given parameters:

Number of moles of K = 2 moles

Unknown:

Number of moles of KCl produced  = ?

Solution:

To solve this problem;

Obtain a balanced chemical equation:

           2K +  Cl₂   →   2KCl ;

Since K is the limiting reactant, its amount will determine the extent of this reaction.

   From the balanced equation;

           2 moles of K will produce 2 moles of KCl

        Given that 2 moles of K reacted, 2 moles of KCl will be produced

5 0
3 years ago
Suppose 2.8 moles of methane are allowed to react with 5 moles of oxygen.
Ronch [10]

Answer : The limiting reagent is O_2

Solution : Given,

Moles of methane = 2.8 moles

Moles of O_2 = 5 moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2

8 0
3 years ago
What types of atoms are in metallic bond?
Tresset [83]
If you know the Table of elements you can see it on.
3 0
2 years ago
Read 2 more answers
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