The molality of the solution is 0.00037 m.
<h3>What is concentration?</h3>
The term concentration refers to the amount of solute in a solution.
We have the following information;
Molarity = 0.335 M
Density = 1.0432 g/mL
Temperature = 20 o C
The molality of the solution is obtained from;
m = 0.335 M × 1.0432 g/mL/ 1000(1.0432 g/mL) - 0.335 M (342 g/mol)
m = 0.344/1043.2 - 114.57
m = 0.344/928.63
m = 0.00037 m
Learn more about molality of solution: brainly.com/question/4580605
I believe the answer is <span>can be elements or compounds
In this case, elements in the decomposition reaction is the substance that cannot be separated into simpler substances.
Compounds, technically act as a reactant in the decomposition reaction, but since the reaction breakdown one substance into two or more, sometimes it exists in the product.</span>
Answer:
![\boxed {\boxed {\sf 0.3 \ mol \ NaNO_3}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%200.3%20%5C%20mol%20%5C%20NaNO_3%7D%7D)
Explanation:
Molarity is a measure of concentration in moles per liter.
![molarity= \frac{moles \ of \ solute}{liters \ of \ solution}](https://tex.z-dn.net/?f=molarity%3D%20%5Cfrac%7Bmoles%20%5C%20of%20%5C%20solute%7D%7Bliters%20%5C%20of%20%5C%20solution%7D)
The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.
- molarity= 1.2 mol NaNO₃/L
- liters of solution=0.25 L
- moles of solute =x
![1.2 \ mol \ NaNO_3/L= \frac{x}{0.25 \ L}](https://tex.z-dn.net/?f=1.2%20%5C%20mol%20%5C%20NaNO_3%2FL%3D%20%5Cfrac%7Bx%7D%7B0.25%20%5C%20L%7D)
We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.
![0.25 \ L *1.2 \ mol \ NaNO_3/L=\frac{x}{0.25 \ L} *0.25 \ L](https://tex.z-dn.net/?f=0.25%20%5C%20L%20%2A1.2%20%5C%20mol%20%5C%20NaNO_3%2FL%3D%5Cfrac%7Bx%7D%7B0.25%20%5C%20L%7D%20%2A0.25%20%5C%20L)
![0.25 \ L *1.2 \ mol \ NaNO_3/L=x](https://tex.z-dn.net/?f=0.25%20%5C%20L%20%2A1.2%20%5C%20mol%20%5C%20NaNO_3%2FL%3Dx)
The units of liters cancel, so we are left with the units moles of sodium nitrate.
![0.25 *1.2 \ mol \ NaNO_3=x](https://tex.z-dn.net/?f=0.25%20%20%2A1.2%20%5C%20mol%20%5C%20NaNO_3%3Dx)
![0.3 \ mol \ NaNO_3=x](https://tex.z-dn.net/?f=0.3%20%5C%20mol%20%5C%20NaNO_3%3Dx)
There are 0.3 moles of sodium nitrate.
A Hydrogen bond will stablish between the protons of the water and the free electron pairs of the electronegative atoms on asparagine, so:
a) can make up to 2 hydrogen bonds, since it has 2 free electron pairs.
b) can make up to 3 hydrogen bonds, since the negative charge makes up for 1 free electron pair aditional to the 2 oxygen already has.
c) can make up to 1 hydrogen bond, since it has 1 free electron pair.
d) since they have no free electron pairs, they cannot establish hydrogen bonds.