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Arturiano [62]
3 years ago
15

A. How can a spinning ball have more lift than one that is not spinning?

Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

It is spinning, making the ball a little more airborn than the one that isn't spinning

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A vector has a magnitude of 46.0 m and points in a direction 20.0° below the positive x-axis. A second vector, , has a magnitude
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Answer with Step-by -step explanation:

We are given that

b.\mid A\mid=46 m

\theta=20^{\circ} below the positive x-axis

Therefore, the angle made by vector A in counter clockwise direction when measure from positive x-axis=x=360-20=340^{\circ}

x-component of vector A=A_x=\mid A\mid cosx=46cos 340=46\times 0.94=43.24

y-Component of vector A=A_y=\mid A\mid sinx=46sin340=46(-0.34)=-15.64

Magnitude of vector B=86 m

The vector B makes angle with positive x- axis=x'=42^{\circ}

x-component of vector B=B_x=86cos42=63.64

y-Component of vector B=B_y=86sin42=57.62

Vector A=A_xi+A_yj=43.24i-15.64j

Vector B=B_xi+B_yj=63.64i+57.62j

Vector C=A+B

Substitute the values

C=43.24i-15.64j+63.64i+57.62j

C=106.88i+41.98j

c.Direction=\theta=tan^{-1}(\frac{y}{x})=tan^{-1}(\frac{41.98}{106.88})=21.5^{\circ}

The direction of the vector C=21.5 degree

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Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another.

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