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Alexxandr [17]
3 years ago
8

Never start a job without knowing the _______and_______ of the chemicals you are working with a) properties and hazards b) SDS a

nd contents c) stability and flash point d) boiling point and flammable limits
Physics
1 answer:
charle [14.2K]3 years ago
6 0

<u>Answer</u>

a) properties and hazards

<u>Explanation</u>

Having information on properties of a chemical helps you know the reactivity of that chemicals.

Most chemicals are very reactive. So you have to be away of their hazards to avoid accidents.


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How is a coil of current carrying wire similar to a bar magnet
zalisa [80]

Answer:

 When an electric current flows, the shape of the magnetic field is very similar to the field of a bar magnet

Explanation:

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What graph shape is this what does the snap tell you
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an object is moving with initial velocity of 5 m/s. After 10 seconds final velocity is 10 m/s. Calculate its acceleration.​
Brut [27]

Answer:

0.5m/s2

Explanation:

acceleration= change in velocity/time taken

= v - u/ t

= 10-5/10

=5/10

= 0.5m/s2

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3 years ago
A person walks 2 miles every day to work, leaving her front porch at 7:00 A.M. and arriving at work at 7:30 A.M. ON the way home
Nataly [62]

Answer:

The displacement is zero miles

Explanation:

The displacement of an object that moves from point A to point B is defined as

d =B-A

Where d is the displacement of the object. The displacement does not depend on the trajectory of the object. It only depends on the linear distance between the end point and the starting point.

In this case we know that the person walks from home to work and then walks from work to home. Therefore, the total displacement is the linear distance between the point where its journey begins and the point where the route ends.

The tour begins on the front porch of your house and ends on the front porch of your house (when you return from work). If we call A to the front porch of the house then the displacement is:

d = A-A = 0

The displacement is zero miles, since the person finishes the journey just where it started (front porch)

7 0
2 years ago
Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on
Romashka [77]

Answer:

q_1=\pm0.03 \mu C and q_2=\pm0.02 \mu C.

Explanation:

According to Coulomb's law, the magnitude of  force between two point object having change q_1 and q_2 and by a dicstanced is

F_c=\frac{1}{4\pi\spsilon_0}\frac{q_1q_2}{d^2}-\;\cdots(i)

Where, \epsilon_0 is the permitivity of free space and

\frac{1}{4\pi\spsilon_0}=9\times10^9 in SI unit.

Before  dcollision:

Charges on both the sphere are q_1 and q_2, d=20cm=0.2m, and F_c=1.35\times10^{-4} N

So, from equation (i)

1.35\times10^{-4}=9\times10^9\frac{q_1q_2}{(0.2)^2}

\Rightarrow q_1q_2=6\times10^{-16}\;\cdots(ii)

After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.

Charges on both the sphere are mean of total charge, i.e

\frac{q_1+q_2}{2}

d=20cm=0.2m, and F_c=1.406\times10^{-4} N

So, from equation (i)

1.406\times10^{-4}=9\times10^9\frac{\left(\frac{q_1+q_2}{2}\right)^2}{(0.2)^2}

\Rightarrow (q_1+q_2)^2=2.50\times10^{-15}

\Rightarrow q_1+q_2=\pm5\times 10^{-8}

As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.

\Rightarrow q_1+q_2=5\times 10^{-8}\;\cdots(iii)

\Rightarrow q_1=5\times 10^{-8}-q_2

The equation (ii) become:

(5\times 10^{-8}-q_2)q_2=6\times10^{-16}

\Rightarrow -(q_2)^2+5\times 10^{-8}q_2-6\times10^{-16}=0

\Rightarrow q_2=3\times10^{-8}, 2\times10^{-8}

From equation (iii)

q_1=2\times10^{-8}, 3\times10^{-8}

So, the magnitude of initial charges on both the sphere are 3\times10^{-8} Coulombs=0.03 \mu C and 2\times10^{-8} Colombs or 0.02 \mu C.

Considerion the nature of charges too,

q_1=\pm0.03 \mu C and q_2=\pm0.02 \mu C.

4 0
3 years ago
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