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2 years ago

Find the speed of a mouse that runs 33 feet in 3 seconds.

Chemistry

1 answer:

NeTakaya2 years ago

6 0

The speed of the mouse is 11 ft/s

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Suppose you have 100 grams of a radioisotope with a half-life of 100 years. How much of the isotope will you have after 200 year

Ulleksa [173]

Amount Remaining Years #half lives
100g 0 0
50 g 100 1
25g 200 2

8 0

3 years ago

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A sample has a pH of -0.248 (yes, it really is possible to have a negative pH). Find

dalvyx [7]

Answer:

pOH= 14.248

[H+]=1.77 M

[OH-]=5.65 x10^-15M

Explanation:

pH+pOH= 14

pOH= 14-pH

pOH=14-(-0.248)

pOH= 14.248

[H+]=10^-pH= 10^-(-0.248)=1.77 M

[OH-]=10^-pOH= 10^-14.248=5.65 x10^-15M

5 0

3 years ago

What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?

Sergeu [11.5K]

Answer:

$\large \boxed{\text{b. 1.5 h}}$

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

$\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt$

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

$\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463 h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}$

4 0

3 years ago

Carbon hexafluroide formula

ikadub [295]

The formula for Hexafluoride is F6S.

4 0

3 years ago

Combustion of hydrocarbons such as methane (CH) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earths atmo

Sveta_85 [38]

Answer:

The balanced chemical reaction of combustion of methane is:

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

734 liters of carbon dioxide gas is produced. .

Explanation:

The balanced chemical reaction of combustion of methane is:

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)$

Mass of methane gas = 0.500 kg = 500 g (1 kg= 1000 g)

Moles of methane = $\frac{500 g}{16 g/mol}=31.25 mol$

According to reaction, 1 mole of methane gas gives 1 mole of carbon dioxide gas. Then 31.25 moles of methane will give :

$\frac{1}{1}\times 31.25 mol=31.25 mol$ of carbon dioxide

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = $\1 atm$

V = Volume of gas =?

n = number of moles of carbon dioxide gas = 31.25 mol

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas =13.0°C=13.0+273.15 K= 286.15 K

Putting values in above equation, we get:

$V=\frac{31.25\times 0.0821 atm L/mol K\times 286.15 K}{1 atm}$

V = 734.15 L ≈ 734 L

734 liters of carbon dioxide gas is produced. .

3 0

3 years ago

Read 2 more answers