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Naya [18.7K]
3 years ago
11

1. What is the momentum of a 1550 kg car that is traveling leftward at a velocity of 15 m/s?

Physics
1 answer:
Alik [6]3 years ago
3 0

Answer:

Momentum, p = 23250 kg m/s

Explanation:

Given that

Mass of a car, m = 1550 kg

Speed pf car, v = 15 m/s

We need to find the momentum of the car. The formula for the momentum of an object is given by :

p = mv

Substituting all the values in the above formula

p = 1550 kg × 15 m/s

p = 23250 kg m/s

So, the momentum of the car is 23250 kg m/s.

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2. 3. 4. 5. 6. 7. A(n)results when a vehicle loses part or all of its grip on the road. is a technique that can be applied when
dexar [7]

Answer:

1) Skid

2)<u> </u>Rocking

3) Oversteer situation

4) Controlled breaking

5) Overdriving headlights

6) Hydroplaning

7) Understeer situation

Explanation:

1) A <u>skid</u> results when a vehicle loses part or all of its grip on the road

2)<u> Rocking</u> is a technique that can be applied when trying to move your vehicle out of deep snow

3) The action of vehicle's rear end sliding out to a side is called an <u>oversteer situation</u>

4) <u>Controlled breaking</u> is a technique of reducing your speed as quick as possible while maintaining control of your vehicle

5) Driving at a speed where the stopping distance of your vehicle is longer than the distance you can see with your headlights is called <u>overdriving headlights</u>

6) <u>Hydroplaning</u> occurs when a tire loses road surface contact and rises on top of water

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7 0
3 years ago
A 30.0 kg child, initially at rest, slides down a 2.0 m tall slide. The child reaches the bottom of the slide with a speed of 6
HACTEHA [7]

Answer:

Explanation:

Total energy is constant

E = mgh + ½mv² + Fd

At the top of the slide, all energy is potential

E = mgh + 0 + 0

At the bottom of the slide, all potential energy has converted to kinetic and work of friction.

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W = 30.0[(9.81)(2.0) - ½6²]

W = 48.6 J

5 0
2 years ago
Two resistors of resistances R1 and R2, with R2&gt;R1, are connected to a voltage source with voltage V0. When the resistors are
ehidna [41]

Answer

The Value of  r  = 0.127

Explanation:

The mathematical representation of the two resistors connected in series is

                               R_T = R_1 +R_2

 And from Ohm law

                           I_s =\frac{ V}{R_T}

                            I_s  = \frac{V_0}{R_1 +R_2} ---(1)

The mathematical representation of the two resistors connected in parallel  is

                    R_T = \frac{1}{R_1} +\frac{1}{R_2}

                          = \frac{R_1 R_2}{R_1 +R_2}

From the question I_p =10I_s

          =>                 I_p =10I_s = \frac{V_0 }{\frac{R_1R_2}{R_1 +R_2} }  = \frac{V_0 (R_1 +R_2)}{R_1 R_2}---(2)

     Dividing equation 2 with equation 1

       =>                 \frac{10I_s}{I_s} =\frac{\frac{V_0 (R_1 +R_2)}{R_1 R_2}}{\frac{V_0}{R_1 +R_2}}

                                  10 = \frac{(R_1+R_2)^2}{R_1 R_2}----(3)

We are told that    r = \frac{R_1}{R_2} \ \ \ \ \  = > R_1 = rR_2

From equation 3  

                            10 = \frac{(1-r)^2}{r}

=> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  1+r^2 + 2r = 10r

=> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ r^2 -8r+1 = 0

Using the quadratic formula

                             r =\frac{-b\pm \sqrt{(b^2 - 4ac)} }{2a}

        a = 1  b = -8 c =1  

                              =  \frac{8 \pm\sqrt{((-8)^2- (4*1*1))} }{2*1}

                               r= \frac{8+ \sqrt{60} }{2}  \ or \  r = \frac{8 - \sqrt{60} }{2}

                              r = \ 7.87\ or \  r \  = \ 0.127

Now  r =  0.127 because it is the least value among the obtained values

                               

                                   

                             

4 0
3 years ago
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