To solve this question, we use the wave equation which is:
C=f*λ
where:
C is the speed;
f is the frequency;
λ is the wavelength
So in this case, plugging in our values in the problem. This will give us:
C = 261.6Hz × 1.31m
= 342.696 m/s is the answer.
When it not to hot it just rite
As per Weins displacement law the wavelength of light for which we get the peak of the graph is always inversely proportional to the temperature.
So we can say
![/lambda = \frac{b}{T}](https://tex.z-dn.net/?f=%2Flambda%20%3D%20%5Cfrac%7Bb%7D%7BT%7D)
So here if temperature becomes more cool then wavelength will increase
here we know that
![\lambda_1 = 8500 A^o](https://tex.z-dn.net/?f=%5Clambda_1%20%3D%208500%20A%5Eo)
![\lambda_2 = 6000 A^o](https://tex.z-dn.net/?f=%5Clambda_2%20%3D%206000%20A%5Eo)
![\lambda_3 = 3500 A^o](https://tex.z-dn.net/?f=%5Clambda_3%20%3D%203500%20A%5Eo)
It means the hottest star out of all three is star 3
and coolest star is star 1
now if we star 2 becomes cooler then it means its temperature will go near to star 1 and hence it will more look like to star 1.
So correct answer is
it will look more like Star 1