Answer:
The acceleration of the body, a = 2193 m/s²
Explanation:
Given,
The mass of the body, m = 0.3 kg
The force acting on the body, F = 657.9 N
The force acting on an object is proportional to the product of mass and acceleration of the body.
F = m x a
Therefore, the acceleration of the body is
a = F / m
= 657.9 N / 0.3 kg
= 2193 m/s²
Hence, the acceleration of the body, a = 2193 m/s²
The answer is c 1386j
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Answer:
Circuit 1 and Circuit 3
Explanation:
If there is 1 Circuit and it runs out of energy, there's another one to produce the power.
Answer:
U = 1 / r²
Explanation:
In this exercise they do not ask for potential energy giving the expression of force, since these two quantities are related
F = - dU / dr
this derivative is a gradient, that is, a directional derivative, so we must have
dU = - F. dr
the esxresion for strength is
F = B / r³
let's replace
∫ dU = - ∫ B / r³ dr
in this case the force and the displacement are parallel, therefore the scalar product is reduced to the algebraic product
let's evaluate the integrals
U - Uo = -B (- / 2r² + 1 / 2r₀²)
To complete the calculation we must fix the energy at a point, in general the most common choice is to make the potential energy zero (Uo = 0) for when the distance is infinite (r = ∞)
U = B / 2r²
we substitute the value of B = 2
U = 1 / r²
m = mass of the car moving in horizontal circle = 1750 kg
v = Constant speed of the car moving in the horizontal circle = 15 m/s
r = radius of the horizontal circular track traced by the car = 45.0 m
F = magnitude of the centripetal force acting on the car
To move in a circle . centripetal force is required which is given as
F = m v²/r
inserting the above values in the formula
F = (1750) (15)²/(45)
F = (1750) (225)/(45)
F = 1750 x 5
F = 8750 N
