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3241004551 [841]
3 years ago
15

Câu 3: Nêu phương pháp hóa học nhận biết các dung dịch không màu sau: (a) HCI, NaOH, H2SO,, NaCl. (b) HNO3. KOH, BaCl. Ca(OH)2.

Ba(NO3)2 (c) MgCl2, KCl, CuCl2, FeCl3, FeCl2 (chỉ dùng một thuốc thử). (d) Na2CO3, BaCl2, NaNO3 (chỉ dùng một thuốc thử)
​
Chemistry
1 answer:
True [87]3 years ago
5 0

Answer:

uvo 8hih8hjfiuwubosbwbhp0heg

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Draw one of the stereoisomers of the product formed when benzaldehyde (c6h5cho) is treated with ph3p═chcooch3.
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This reaction is known as Wittig Reaction. A powerful reaction for the synthesis of Alkene. In question the starting materials are aldehyde and a Phosphorous Ylide. Ylide when reacted with aldehyde produces a four membered ring which on rearrangement gives Alkene and triphenylphosphine oxide. Phosphorous having great affinity toward the oxygen is the driving force of this rearrangement. The reaction along with product (highlighted blue) is as follow,

8 0
3 years ago
How many neutrons are in the nucleus of an atom that has an atomic mass of 36 and an atomic number of 25?
elixir [45]

Answer:

Neutrons = 11

Explanation:

To get the number of neurons an element has you have to subtract the number of protons from the atomic mass of that element.

The number of protons is equal to the atomic number of that element.

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So the number of protons is 25

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6 0
3 years ago
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What are the equilibrium concentrations of pb2+ and f– in a saturated solution of lead(ii) fluoride if the ksp of pbf2 is 3.20×1
erica [24]
Answer is:  the equilibrium concentrations fluorine anion are 0.004 M and lead cation are 0.002 M.<span>
Chemical reaction: PbF</span>₂(aq) → Pb²⁺(aq) + 2F⁻(aq).<span>
Ksp = 3,2·10</span>⁻⁸.
[Pb²⁺] = x.
[F⁻] = 2[Pb²⁺] = 2x<span>
Ksp = [Pb²</span>⁺] · [F⁻]².
Ksp = x · 4x².
3,2·10⁻⁸ = 4x³.
x = ∛3,2·10⁻⁸ ÷ 4.
x = [Pb²⁺] = 0,002M = 2·10⁻³ M.
[F⁻] = 2 · 0,002M = 0,004 M = 4·10⁻³ M.

6 0
3 years ago
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Who ever gets right gets brainliest
grandymaker [24]

Answer:

it's subduction

Explanation:

i know this because I just do lol

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What is orbital theory of bonding in metals
lianna [129]
Metals of Group 1 donate 1 electron from its ns orbital to form ionic bond, where n is the no. of its outermost shell. 
Metals of Group 2<span> donate 2 electrons from its ns orbital to form ionic bond, where n is the no. </span>of its <span>outermost shell. </span>
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