In my opinion it does. The more water the pot holds, the longer you need to wait for it to freeze. Since there is more water, some parts may not be completely frozen. An experiment you can try is to get an ice cube container and a pot. fill both of them and put them in the freezer for the same amount of time. When you take it out, the ice cubes should be frozen leaving the pot with cold water.
For 2 draw the molucules very close together. because in soilds the molucules are VERY close to gether.
and for 3 Draw them with a lot of space apart from each other. Molucules move freely and openly in air and space.
Hope this helps! Please mark as brainliest! Thanks!! :D
The correct match of each item to the clean water regulation it describes is as follows:
- Regulates pollutants discharged into surface waters: Clean water act
- Covers both surface and ground waters: Safe drinking water act
- Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
- Funds sewage treatment plants: Clean water act
<h3>What are the functions of clean water regulation?</h3>
Clean Water Act (CWA) is a regulatory body that establishes the basic structure for the regulation of pollutants discharge and maintenance of quality standards of the surface waters.
On the other hand, the Safe Drinking Water Act was founded to oversee the protection of the quality drinking water. The regulatory body is primarily concerned with potable water all waters, whether from above ground or underground sources.
Therefore, the correct match of each item to the clean water regulation it describes is as follows:
- Regulates pollutants discharged into surface waters: Clean water act
- Covers both surface and ground waters: Safe drinking water act
- Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
- Funds sewage treatment plants: Clean water act
Learn more about clean water regulation at: brainly.com/question/2142268
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Answer:
a) x(t) = 10t + (2/3)*t^3
b) x*(0.1875) = 10.18 m
Explanation:
Note: The position of the horse is x = 2m. There is a typing error in the question. Otherwise, The solution to cubic equation holds a negative value of time t.
Given:
- v(t) = 10 + 2*t^2 (radar gun)
- x*(t) = 10 + 5t^2 + 3t^3 (our coordinate)
Find:
-The position x of horse as a function of time t in radar system.
-The position of the horse at x = 2m in our coordinate system
Solution:
- The position of horse according to radar gun:
v(t) = dx / dt = 10 + 2*t^2
- Separate variables:
dx = (10 + 2*t^2).dt
- Integrate over interval x = 0 @ t= 0
x(t) = 10t + (2/3)*t^3
- time @ x = 2 :
2 = 10t + (2/3)*t^3
0 = 10t + (2/3)*t^3 + 2
- solve for t:
t = 0.1875 s
- Evaluate x* at t = 0.1875 s
x*(0.1875) = 10 + 5(0.1875)^2 + 3(0.1875)^3
x*(0.1875) = 10.18 m
