Suppose that you are standing on a train accelerating at 0.20g (where g is the acceleration due to gravity). What minimum coeffi
1 answer:
Answer:
0.2
Explanation:
The given parameters are;
The acceleration of the train, a = 0.2·g
The mass of the person standing on the train = m
Let μ represent the coefficient of static friction, we have;
The force acting on the person, F = m × a = m × 0.2·g
The force of friction acting between the feet and the floor, = m·g·μ
For the person not to slide we have;
The force acting on the person = The force of friction acting between the feet and the floor
F =
∴ m × 0.2·g = m·g·μ
From which we get;
0.2 = μ
The coefficient of static friction that must exist between the feet and the floor if the person is not to slide, μ = 0.2.
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Answer:
λ = 1.388 x 10⁻⁶ m = 1388 nm
Explanation:
We can use the Young's Double Slit experiment formula here to solve this numerical:
where,
λ = wavelength = ?
Δx = distance between adjacent bright fringes = 1.62 cm = 0.0162 m
d = slit separation = 0.24 mm = 0.00024 m
L = distance from screen to slits = 2.8 m
Therefore,
<u>λ = 1.388 x 10⁻⁶ m = 1388 nm</u>
Answer:
1109m
Explanation:
The distance h₁ traveled by the rocket during acceleration:
The velocity v₁ at this height h₁:
When the rocket runs out of fuel, energy is conserved:
Solving for h₂: