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Lapatulllka [165]
4 years ago
6

What variables affect whether or not the fishing weight floats?

Chemistry
1 answer:
Degger [83]4 years ago
7 0

Answer:

Density

Explanation:

If the fishing weight is more dense than the water, it will sink and if it less dense it will float. hope this helps :)

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3.How many grams of lithium nitrate will be needed to
ZanzabumX [31]

Answer:

m_{LiNO_3}=314gLiNO_3

Explanation:

Hello!

In this case, for the given chemical reaction:

Pb(SO_4 )_2, + 4 LiNO_3 \rightarrow Pb(NO_3)_4, + 2 Li_2 SO_4

We can see a 4:2 mole ratio between lithium nitrate (68.946 g/mol) and lithium sulfate (109.94 g/mol); in such a way, via stoichiometry, the required mass of lithium nitrate to make 250 g of lithium sulfate turns out:

m_{LiNO_3}=250gLi_2SO_4*\frac{1molLi_2SO_4}{109.94gLi_2SO_4} *\frac{4molLiNO_3}{2molLi_2SO_4} *\frac{68.946gLiNO_3}{1molLiNO_3}\\\\m_{LiNO_3}=314gLiNO_3

Best regards!

4 0
3 years ago
A substance changes from a solid to a liquid at its
8090 [49]

Answer:

Melting point

Explanation:

8 0
3 years ago
Read 2 more answers
Two atoms that have the same number of protons must be the same_________.
iren2701 [21]
Must be the same ELEMENT
8 0
4 years ago
Read 2 more answers
Enter your answer in the provided box. Calcium hydroxide may be used to neutralize (completely react with) aqueous hydrochloric
NNADVOKAT [17]

Answer:

49.95 g of HCl

Explanation:

Let's formulate the chemical equation involved in the process:

Ca(OH)2 + 2 HCl → CaCl2 + 2 H2O

This means that we need 1 mole of Calcium hydroxide to neutralize 2 moles of hydrochloric acid. From this, we calculate the quantity of HCl moles that would be neutralized by 0.685 moles of Ca(OH)2

1 mole Ca(OH)2 ---- 2 moles HCl

0.685 moles Ca(OH)2 ---- x = 1.37 moles HCl

Now that we know the quantity of HCl moles that would react, let's calculate the quantity of grams this moles represent:

1 mole of HCl ---- 36.46094 g

1.37 moles ------ x = 49.95 g of HCl

3 0
3 years ago
In a given sample, hydrogen gas effuses four times faster than the other gas present in the mixture. What is the molar mass and
Greeley [361]
We need to use the effusion formula. I have attached a picture of what this formula looks like because it is a bit hard to type. 

effusion formula---> Rate 1/ rate 2= √(M2/M1)

as the questions states, hydrogen gas rate is 4 times the rate of the other gas. so, let call gas 1 the unknown and gas 2 the hydrogen

Rate 1= 1
Rate 2= 4

M1=??
M2= 2 grams

now let's plug in the values and solve for the unknown

1/4 = √(2/x)

x= 32 grams

with the choices given, the gases are either O₂, N₂ or O₃.

O₂ is the one whose mass is 32 because oxygen atomic mass in the periodic table is 16 grams. since we have two oxygens, then 16 x 2= 32

the answer is "<span>32 grams and oxygen "</span>



8 0
3 years ago
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