Answer:
n = 0.651 mol
Explanation:
Given data:
Volume of CO₂ = 14.6 L
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Number of moles of CO₂ = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
by putting values,
1 atm × 14.6 L = n × 0.0821 atm.L/ mol.K × 273.15 K
14.6 L. atm = n × 22.43atm.L/ mol
n = 0.651 mol
A.movement and protection
Answer:
24.47 L
Explanation:
Using the general gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = 0.0821 Latm/molK
T = temperature (K)
According to the provided information in this question,
P = 1.0 atm
V = ?
n = 1 mol
T = 25°C = 25 + 273 = 298K
Using PV = nRT
V = nRT ÷ P
V = 1 × 0.0821 × 298 ÷ 1
V = 24.465 ÷ 1
V = 24.465
V = 24.47 L