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marissa [1.9K]
3 years ago
8

PLEASE LOOK AT POST MARKING BRAINIEST

Chemistry
1 answer:
Charra [1.4K]3 years ago
8 0

Explanation:

             MgF₂ + ___Li₂CO₃  → ___MgCO₃ + ___LiF

1. Every chemical reactions obey the law of conservation of matter. The law states that "matter can neither be created not destroyed but transformed from one form to another".

 When chemical reactions are balanced, they simply obey the law of conservation of matter and mass. This makes makes measurement easy to make when carrying out experiments. One can easily deduce the amount of reactants to be used and the products expeceted

2                 MgF₂ + ___Li₂CO₃  → ___MgCO₃ + ___LiF

  to balance the equation:

  • check if the equation is balanced.
  • Put a,b,c and d before each of the products and reactants.

                  aMgF₂ + bLi₂CO₃  → cMgCO₃ + dLiF

  • The coefficients are needed to balance the equation:

  conserving Mg:       a = c

                       F:         2a = d

                       Li:        2b = d

                        C:        b = c

                        O:       3b = 3c

  • From the above:

       let us assume that    a=1

         then                         c = 1

                                          b = 1

                                          d =2

     

                         MgF₂ + Li₂CO₃  → MgCO₃ + 2LiF

Learn more:

Balanced chemical reaction brainly.com/question/11102790

#learnwithBrainly

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marusya05 [52]

Answer: 27.09 ppm and 0.003 %.

First, <u>for air pollutants, ppm refers to parts of steam or gas per million parts of contaminated air, which can be expressed as cm³ / m³. </u>Therefore, we must find the volume of CO that represents 35 mg of this gas at a temperature of -30 ° C and a pressure of 0.92 atm.

Note: we consider 35 mg since this is the acceptable hourly average concentration of CO per cubic meter m³ of contaminated air established in the "National Ambient Air Quality Objectives". The volume of these 35 mg of gas will change according to the atmospheric conditions in which they are.

So, according to the <em>law of ideal gases,</em>  

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the constant gas (0.082057 atm L / mol K)

The moles of CO will be,

n = 35 mg x \frac{1 g}{1000 mg} x \frac{1 mol}{28.01 g}

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We clear V from the equation and substitute P = 0.92 atm and

T = -30 ° C + 273.15 K = 243.15 K

V =  \frac{0.00125 mol x 0.082057 \frac{atm L}{mol K}  x 243 K}{0.92 atm}

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V = 0.0271 L x \frac{1000 cm^{3} }{1 L} = 27.09 cm³

<u>Then the acceptable concentration </u><u>c</u><u> of CO in ppm is,</u>

c = 27 cm³ / m³ = 27 ppm

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c = 27.09 \frac{cm^{3} }{m^{3} } x \frac{1 m^{3} }{1 000 000 cm^{3} } x 100%

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<u>Answer:</u> The volume of solution required is 0.0275 L.

<u>Explanation:</u>

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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We are given:

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Putting values in above equation, we get:

0.08mol/L=\frac{0.022mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=0.0275L

Hence, the volume of solution required is 0.0275 L.

6 0
3 years ago
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