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Sunny_sXe [5.5K]
3 years ago
13

Find the coefficient of x^4 in the expansion of (1 + 2x + 3x^3)^10?

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0
(1+2x+3x^3)^{10}

The only possible configurations of terms that contribute to generating the x^4 term in the expansion are given by the multinomial theorem to be

\left(\dbinom{10}{6,4,0}(1)^6(2x)^4(3x^3)^0+\dbinom{10}{8,1,1}(1)^8(2x)^1(3x^3)^1\right)x^4

where

\dbinom{10}{k_1,\ldots,k_m}=\dfrac{10!}{k_1!\cdots k_m!}

Simplifying a bit gives a coefficient of

\dbinom{10}{6,4,0}(2)^4+\dbinom{10}{8,1,1}(2)(3)
16\dbinom{10}{6,4,0}+6\dbinom{10}{8,1,1}
16\dfrac{10!}{6!4!0!}+6\dfrac{10!}{8!1!1!}
16(5\times3\times2\times7)+6(10\times9)=3900
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Hello : 
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an equation of this tangent is : y - (-4) = (3/4)(x-3)

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In order for the parallelogram to be a rhombus, x=?
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6 0
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X/3 = 5/x-1 cross multiply
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Please please helpp i will mark brainliest!!! 100 points !! ill mark brainliest if its correct.
Paraphin [41]

Answers and Step-by-step explanations:

1. We need to plug in values of x into the functions f(x) and g(x):

f(2) = 2.5 * 2 - 10.5 = -5.5                         g(2) = 64 * (0.5^2) = 16

f(3) = 2.5 * 3 - 10.5 = -3                            g(3) = 64 * (0.5^3) = 8

f(4) = 2.5 * 4 - 10.5 = -0.5                         g(4) = 64 * (0.5^4) = 4

f(5) = 2.5 * 5 - 10.5 = 2                             g(5) = 64 * (0.5^5) = 2

f(6) = 2.5 * 6 - 10.5 = 4.5                          g(6) = 64 * (0.5^6) = 1

2.

(a) Notice that at 14 on the x-axis, the blue line is above 4. Meanwhile, at 14, the red line is less than 2. Obviously, we can see that if the printed ad revenue was less than 2 and the online ad revenue was greater than 4, that's more than a double, so the lead marketing executive is correct.

(b) The approximate year that the revenues were equal is the place where the lines intersect. It's approximately at Year 7.5.

3.

(a) The Western Beach is clearly decreasing; it is decreasing by 2 ft per year. Meanwhile, the Dunes Beach is clearly increasing; it's increasing by 5 ft per year. (I'm not sure what kinds of "patterns" you're looking for).

(b) Year 11 and 12; this is because here, Western is going from 78 to 76 ft and Dunes is going from 75 to 80, so they'll likely coincide sometime in that time interval.

(c) One thing you can do is to create equations (of the form y = mx + b) for each of the beaches and then set those linear equations equal to each other.

6 0
3 years ago
Read 2 more answers
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