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Sunny_sXe [5.5K]
3 years ago
13

Find the coefficient of x^4 in the expansion of (1 + 2x + 3x^3)^10?

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0
(1+2x+3x^3)^{10}

The only possible configurations of terms that contribute to generating the x^4 term in the expansion are given by the multinomial theorem to be

\left(\dbinom{10}{6,4,0}(1)^6(2x)^4(3x^3)^0+\dbinom{10}{8,1,1}(1)^8(2x)^1(3x^3)^1\right)x^4

where

\dbinom{10}{k_1,\ldots,k_m}=\dfrac{10!}{k_1!\cdots k_m!}

Simplifying a bit gives a coefficient of

\dbinom{10}{6,4,0}(2)^4+\dbinom{10}{8,1,1}(2)(3)
16\dbinom{10}{6,4,0}+6\dbinom{10}{8,1,1}
16\dfrac{10!}{6!4!0!}+6\dfrac{10!}{8!1!1!}
16(5\times3\times2\times7)+6(10\times9)=3900
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Twice a number plus twice a second number is 310. The difference between the numbers is 55. Find the numbers by writing and solv
yan [13]

The numbers are 105 and 50

<em><u>Solution:</u></em>

Let "x" be the first number

Let "y' be the second number

Twice a number plus twice a second number is 310

Therefore,

twice of x + twice of y = 310

2x + 2y = 310 ---------- eqn 1

The difference between the numbers is 55

x - y = 55 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 2,

x = 55 + y ------ eqn 3

<em><u>Substitute eqn 3 in eqn 1</u></em>

2(55 + y) + 2y = 310

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4y = 200

<h3>y = 50</h3>

<em><u>Substitute y = 50 in eqn 3</u></em>

x = 55 + 50

<h3>x = 105</h3>

Thus the numbers are 105 and 50

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Using it's concept, the domain of the function shown in the graph is:

B. -6 \leq x \leq 6.

<h3>What is the domain of a function?</h3>

The domain of a function is the set that contains all possible input values for the function. In a graph, the domain is the set that contains all values of x.

From this graph, the function is defined for values of x between -6 and 6, hence the domain is given by:

B. -6 \leq x \leq 6.

More can be learned about the domain of a function at brainly.com/question/10891721

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