Answer:
Explanation:
Some theoretical knowledge is required here. We should understand that whenever we plot the natural logarithm, ln, of a concentration vs. time and obtain a straight line, this indicates a first-order reaction. That said, since this is the case here, we have a first-order reaction with respect to .
The linear equation has the following terms:
It is a linear form of the integrated first-order law equation:
Therefore, the rate constant, k, is:
The natural logarithm of initial molarity is:
Using the equation, we may substitute for t = 600 s and obtain the natural logarithm of the concentration at that time:
Take the antilog of both sides to find the actual molarity:
