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OlgaM077 [116]
3 years ago
9

See attached image down below

Chemistry
1 answer:
cestrela7 [59]3 years ago
6 0
I think the answer will be 60 and the reason why is because
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How many electrons does one neutrally charged atom of argon have?
padilas [110]

Answer:

A. 18

Explanation:

A neutral charged atom is an atom with 0 charge.

Anyway, first look at the periodic table and find Argon.

After you find Argon, look at its Atomic number.

Its Atomic number is 18.

And a neutral atom of Argon has 0 charge.

So we need 18 electrons for Argon to cancel out and become neutral.

Basic math:

18 +( -18) = 0

Therefore, the correct answer is A. 18

Hope it helped!

7 0
3 years ago
Read 2 more answers
The 4 in formula 4H2O is a<br><br>1. coefficient<br>2. subscript<br>3. superscript<br>4. binomial​
Rom4ik [11]
1. Coefficient

Since it is a number that constant for the given substance
7 0
3 years ago
A scientist has two solutions, which she has labeled solution a and solution
klio [65]
Let's make ;
A = ounces solution A
B = ounces solution B


total number of ounces: 
A + B = 120

concentration:
0.65A + 0.80B = 0.7(120)

 Substitute A for 120 - B in the second equation to combine them.

0.65(120 - B) + 0.80B = 84
78 - 0.65B + 0.80B = 84
0.15B = 84 - 78
0.15B = 6
B = 6/0.15
 
B = 40 ounces
Then... A = 120 - 40
A = 60 ounces

8 0
3 years ago
For the following reaction NaOH + Fe(NO3)3 - Fe(OH)3 + NaNO3 , what compound is the precipitate
likoan [24]
Compound Noah+Noah
7 0
3 years ago
compute the mass-specific enthalpy change associated with Nz that is undergoing a change in state from 400 k to 800 k
Kitty [74]

Answer:

The correct answer is "430 kJ/kg". A further explanation is given below.

Explanation:

The given values are:

T₁ = 400 k

T₂ = 800 k

The average temperature will be:

= \frac{T_1+T_2}{2}

= \frac{400+800}{2}

= 600 \ k

From table,

At 600 k the C p will be = 1.075

Now,

⇒ The specific enthalpy = Cp(T_2-T_1)

⇒                                \Delta h=1.075 (800-700)

⇒                                      =430 \ kJ/kg

8 0
3 years ago
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