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emmasim [6.3K]
3 years ago
11

The shadow zone exists because ?

Chemistry
1 answer:
lana66690 [7]3 years ago
6 0
At almost the opposite point on the Earth's surface, the "P" waves reappear. The shadow zone exists because the waves are refracted as they pass through the boundary between the mantle and the core and are diverted from their original paths.
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140000 rounded to 3 sig gigs
attashe74 [19]
1.40E+5 (140000)
I believe this is right
8 0
3 years ago
Why does lithium form only lithium oxide and not peroxide or superoxide ​
Alexandra [31]

Answer:

Lithium does form a peroxide as well as an oxide on burning in air and I suspect the low temperature reaction with air forms a significant amount of peroxide.

8 0
3 years ago
A container of gas has a volume of 140.0 cm3 at a temperature of 27.0°C. If the
Vitek1552 [10]

Answer:

285.185 (.185 repeating) cm^3

Explanation:

To get the answer, you divide 140 by 27 to get 5.185 (.185 repeating). Then, you multiply 5.185 (.185 repeating) by 55 and get 285.185 (.185 repeating) cm^3. Please use ^ next time to indicate exponents.

8 0
3 years ago
A gas under an initial pressure of 0.60 atm is compressed at constant temperature from 27 L to 3.0 L. The final pressure becomes
kherson [118]
The answer is.... : 5.4 atm
3 0
3 years ago
Read 2 more answers
A newly found element with the symbol J has two naturally occurring isotopes. Isotope one has an atomic mass of 139.905 amu and
oksian1 [2.3K]

Answer:

The mass of the element is 141.03701 amu

Explanation:

The catch here is that it notes a " newly found element. " Otherwise you could just refer to the average atomic mass of the element in the periodic table, and receive your solution in a much faster way.

The first isotope has an atomic mass of 139.905 amu, and a respective percent abundance of 37.25%. The second isotope has an atomic mass of 141.709 amu, and the remaining percent abundance, 100% - 37.25% = 62.75% ( given ). We can calculate the mass of the unknown element by associating each percentage with the mass of their respective isotope, over 100%.

Mass = ( ( 139.905 amu )( 37.25% ) + ( 141.709 amu )( 62.75% ) )/ 100,

Mass = ( ( 5211.46125 ) + ( 8892.23975 ) ) / 100,

Mass = ( 14103.701 ) / 100 = 141.03701 amu

5 0
3 years ago
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