As the H bond of the butanol is more effective and strong than Van der Waals forces of the ether the surface tension in alcohol is more intensive.
So the correct answer is e)
0.753 is the answer for this question
10^(-0.123)=0.753
"The objects weight changes, but the mass stays the same" is the one statement among the following choices given in the question that <span>is true about the object. The correct option among all the options that are given in the question is the first option or option "a". I hope the answer has come to your help.</span>
This problem uses the relationship between Kb and the the dissociation constants which is expressed as Kw = KaKb. Calculations are as follows:
<span>
Kb = KaKb
</span><span>1.00 x 10^-14 = 7.2 x 10^-4(x)
</span><span>x = 1.39 x 10^-11
</span><span>
We now need to calculate the [OH¯] using the Kb expression:
</span>1.39 x 10^-11 = x^2 / (0.30 - x)
<span>
The denominator can be neglected. </span><span>Thus, x is 3.73 x 10^-6.
</span><span>
pOH = -log 3.73 x 10^-6 = 5.43
p</span><span>H = 14-5.43 = 8.57</span>