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Elena L [17]
3 years ago
7

The mass of M1 = 12 Daltons and it has a speed of v1 = 200 m/s. The mass of M2 = 4 Daltons. What was the total momentum of the s

ystem consisting of both masses before the collision (in Dalton meters per second, assume positive to the right and negative to the left)?

Physics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

The total momentum is  p__{T }} =(2400  -4 v_2) \ Dalton \cdot m/s

Explanation:

The diagram illustration this  system is shown on the first uploaded image (From physics animation)

From the question we are told that

     The mass of the first object is M_1 =  12 \ Dalton

      The speed of the first mass is v_1 =  200 \ m/s

      The mass of the second object is  M_2 =  4 \ Dalton

      The speed of the second object is  assumed to be  - v_2

The total momentum of the system is the combined momentum of both object which is mathematically represented as

           p__{T }} = M_1 v_1 + M_2 v_2

   substituting values

            p__{T }} = 12 * 200 + 4 * (-v_2)

            p__{T }} =(2400  -4 v_2) \ Dalton \cdot m/s

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