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DochEvi [55]
3 years ago
11

Two birds have the same mass but one has bigger feet. How would pressure that they produce on the ground be different ?

Physics
1 answer:
Mama L [17]3 years ago
3 0

Answer:

the pressure per square inch is greater from the smaller feet.

Explanation:

different weight distribution

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Without heat from the Sun, the water cycle would A) reverse. B) not work. C) slow down. D) not be affected.
Tanzania [10]
B) not work ,because the water would freeze
4 0
3 years ago
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Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
Elena L [17]

Answer:

19 m/s

Explanation:

The complete question requires the final speed to be calculated.

Velocity is the rate and direction at which an object moves. Acceleration is the rate of change of velocity per unit time and can be calculated by the difference in velocity over a given time.

For this question, first the unknown acceleration must be calculated and used to determine the final velocity

Step 1: Calculate the acceleration

a=\frac{v_{2}-v{1}}{t_{1}}

a=\frac{11-7}{8}

a=\frac{4}{8}

a=0.5 m/s^{2}

Step 2: Calculate the velocity using the acceleration calculated above

a=\frac{v_{3}-v{2}}{t_{2}}

0.5=\frac{v_{3}-11}{16}

v_{3}=19 m/s

3 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
3 years ago
After the collision, car 1 has a final velocity of 6m/s south. What is the final velocity of car2?
dedylja [7]
I’m almost 100 percent sure it’s the first one
4 0
3 years ago
A 1,200 kg car accelerates at 3 m/s2. What net force is the car experiencing during thisacceleration?0 3600 NO 2000 N0 2400 NOON
Mama L [17]

m = mass = 1,200 kg

A = acceleration = 3 m/s^2

Apply Newton's second law:

Force = mass x acceleration

F = 1,200 x 3 =3600 N

The net force the car experiences is 3600 N

5 0
1 year ago
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