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dybincka [34]
4 years ago
15

Please solve this with the steps.

Mathematics
2 answers:
alex41 [277]4 years ago
8 0
3/4x + 9/4 = 9

Subtract 9/4 from both sides.

3/4x = 9 - 9/4

Simplify.

3/4x = 36/4 - 9/4

Simplify.

3/4x = 27/4

Multiply both sides by 4/3.

x = 27/4 × 4/3

Simplify.

x = 9

~Hope I helped!~
bija089 [108]4 years ago
5 0
Subtract 9/4 from both sides
3/4x=6 3/4
Multiply them by 4/3
X=9
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4 years ago
Plot two numbers on the numberline that are 7 units from 3<br><br> Is this correct?
dalvyx [7]

Answer:

-4 and 10

Step-by-step explanation:

It is 7 units from 3 not 3 the number itself

5 0
3 years ago
Read 2 more answers
B) 2x² - 4x + 3 = 0<br> a) x² + 3x – 10 = 0
kozerog [31]

Answer:

a. x = 2 , x = -5

b. no real roots

Step-by-step explanation:

<u>a. x² + 3x – 10</u>

= x² - 2x + 5x - 10

= x (x²/x - 2x/x) + 5 (5x/5 - 2*5/5)

= (x - 2) (x + 5)

x - 2 = 0                            x + 5 = 0

 + 2    +2                             -5     -5

--------------                         ---------------

x = 2                                   x = -5

x = 2 , x = -5

<u>b. 2x² - 4x + 3 </u>

This can't be solved because the equation has no real roots, and also the discriminant is negative.

3 0
3 years ago
What are the solutions to the quadratic equation (5y +6) 2= 24?
boyakko [2]

Answer:

y=-2.18,-0.22

Step-by-step explanation:

We have been given the equation

(5y+6)^2=24

Take square root both sides. When ever we take square root, we include plus minus sign

\sqrt{(5y+6)^2}=\pm\sqrt{24}\\\\5y+6=\pm2\sqrt6

Now, subtract 6 to both sides of the equation

5y=-6\pm2\sqrt6

Divide both sides by 5

y=\frac{1}{5}(-6\pm2\sqrt6)

y=\frac{1}{5}(-6+2\sqrt6),y=\frac{1}{5}(-6-2\sqrt6)

In decimal we have

y=-2.18,-0.22



3 0
3 years ago
Evaluate [(21 + 6) − 32] ÷ 9 ⋅ 2.
nevsk [136]
If you follow PEMDAS your answer would be 3.6.
8 0
3 years ago
Read 2 more answers
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