Answer:
+125.4 KJmol-1
Explanation:
∆H C4H10(g) = -2877.6kJ/mol
∆H C(s)=-393.5kJ/mol
∆H H2(g) = -285.8
∆H reaction= ∆Hproducts - ∆H reactants
∆H reaction= (-2877.6kJ/mol) - [4(-393.5kJ/mol) +5(-285.8)]
∆H reaction= +125.4 KJmol-1
Answer:
»Climatic change leads to malnutrition.
e.g when its cold season, osmoregulation decreases and rate of metabolism declines.
This is because the enzymes lack that optimum temperature for their catalytic activity to take place hence improper digestion.
»Leads to promotion of predation in ecosystem.
such as reptiles e.g snakes, lizards get away from shelters on cold days since they are cold blooded, hence their predators such as animals, birds increase.
Answer:
The answer to your question is 8.21 g of H₂O
Explanation:
Data
mas of water = ?
mass of hydrogen = 4.6 g
mass of oxygen = 7.3 g
Balanced chemical reaction
2H₂ + O₂ ⇒ 2H₂O
Process
1.- Calculate the atomic mass of the reactants
Hydrogen = 4 x 1 = 4 g
Oxygen = 16 x 2 = 32 g
2.- Calculate the limiting reactant
Theoretical yield = H₂/O₂ = 4 / 32 = 0.125
Experimental yield = H₂/ O₂ = 4.6/7.3 = 0.630
From the results, we conclude that the limiting reactant is Oxygen because the experimental yield was higher than the theoretical yield.
3.- Calculate the mass of water
32 g of O₂ ---------------- 36 g of water
7.3 g of O₂ --------------- x
x = (7.3 x 36) / 32
x = 262.8 / 32
x = 8.21 g of H₂O
Answer:
37.5 L
Explanation:
Initial Volume, V1 = 15L
Initial Pressure P1 = 4.5 atm
Final Pressure, P2 = 1.8 atm
Final Volume V2 = ?
The relationship between these variables is given as;
P1V1 = P2V2
V2 = PIV1 / P1
Inserting the values;
V2 = 4.5 * 15 / 1.8
V2 = 37.5 L
