distance to the star Betelgeuse: 640 ly
As we know that

also we know that


So the distance of Betelgeuse = 640 ly

distance to the star VY Canis Majoris: 


distance to the galaxy Large Magellanic Cloud: 49976 pc


now we have


distance to Neptune at the farthest: 4.7 billion km

now the order of distance from least to greatest is as following
1. distance to Neptune at the farthest
2. distance of Betelgeuse
3. distance to the star VY Canis Majoris
4. distance to the galaxy Large Magellanic Cloud
Answer: about 100 km[kilometers] thick
Explanation:
The shape is connected in parallel so;
5.1) Ans;

5.2) Ans;

I hope I helped you^_^
Density is defined as (mass) per unit (volume). So in order to calculate
the density of a glob of some substance, you pretty much have to measure
its mass and its volume.
You need to use Planck's law:
E = h·υ = (h·c)/λ
Without making all the calculations, a fraction is bigger than another when the denominator is smaller. Therefore you need to find the smallest wavelength (λ) which is 450nm.
You could also be helped by colors: in order of decreasing energy, you have blue - green - yellow - red.
In any case, the correct answer is a).